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## Main Question or Discussion Point

I'm trying to work out the number of effective degrees of freedom in the LSS (Light Stop Scenario) within the MSSM (Minimal Supersymmetric Standard Model). To make sure that I understand the concept I am trying to reproduce the number of dofs in the Standard Model.

The way I count them the degrees of freedom from the different particle species are:

Scalar, spin-0 (Higgs boson): 1

Massless vector bosons (Photons, gluons): 2

Massive vector bosons (W+, W-, Z): 3

Leptons: 2 (spin up and down) x 2 (particle/antiparticle) = 4

Quarks: 2 (spin up and down) x 2 (particle/antiparticle) x 3 (colour) = 12

There are 8 gluon, 6 quark and 6 lepton species in the SM so I get:

Total degrees of freedom = 1 + 2 + ( 8 x 2) + ( 3 x 3) + ( 6 x 4 ) + (6 x 12) = 128

Is this right??

Thanks,

Melmoth

The way I count them the degrees of freedom from the different particle species are:

Scalar, spin-0 (Higgs boson): 1

Massless vector bosons (Photons, gluons): 2

Massive vector bosons (W+, W-, Z): 3

Leptons: 2 (spin up and down) x 2 (particle/antiparticle) = 4

Quarks: 2 (spin up and down) x 2 (particle/antiparticle) x 3 (colour) = 12

There are 8 gluon, 6 quark and 6 lepton species in the SM so I get:

Total degrees of freedom = 1 + 2 + ( 8 x 2) + ( 3 x 3) + ( 6 x 4 ) + (6 x 12) = 128

Is this right??

Thanks,

Melmoth