- #1
Messenger
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In General relativity: an introduction for physicists, the authors derive Newtonian gravity from the EFE, but then they also give a short statement that inserting in the cosmological constant derives down to:
[tex]
\vec{g}=-\nabla\Phi=-\frac{GM}{r^{2}}\hat{\vec{r}}+\frac{\Lambda c^{2}r}{3}\hat{\vec{r}}.
[/tex]
I don't see how they end up with a 3 in the denominator. Probably am missing something simple. Any help?
[tex]
\vec{g}=-\nabla\Phi=-\frac{GM}{r^{2}}\hat{\vec{r}}+\frac{\Lambda c^{2}r}{3}\hat{\vec{r}}.
[/tex]
I don't see how they end up with a 3 in the denominator. Probably am missing something simple. Any help?