Density of States: 1-Dim Linear Phonons & Electrons Differences

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SUMMARY

The discussion focuses on the calculation of the density of states for 1-dimensional linear phonons and electrons, specifically with N atoms. The user initially presents the equations for density of states, noting that for phonons, the equation is dN = \frac{dk}{\frac{2π}{a}} = \frac{a}{2π}dk, while for electrons, it is dN = 2 \cdot \frac{dk}{\frac{2π}{a}} = \frac{a}{π}dk. The confusion arises from the application of the Pauli exclusion principle, which allows two electrons to occupy the same state if they have opposite spins. The user acknowledges that their calculation does not account for the spin component, which is crucial for accurately determining the density of states for electrons.

PREREQUISITES
  • Understanding of density of states in solid-state physics
  • Familiarity with the Pauli exclusion principle
  • Knowledge of 1-dimensional K-space and periodic boundary conditions
  • Basic mathematical skills for manipulating equations
NEXT STEPS
  • Study Kittel's "Introduction to Solid State Physics" for detailed explanations on density of states
  • Learn about the implications of the Pauli exclusion principle on electron states
  • Explore the derivation of density of states for various dimensional systems
  • Investigate the role of spin in quantum mechanics and its effect on particle statistics
USEFUL FOR

Students and researchers in solid-state physics, particularly those studying phonon and electron interactions, as well as anyone interested in the mathematical foundations of quantum mechanics.

cozycoz
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I'm to get the density of states of 1-dim linear phonons, with N atoms. I think it's a lot similar to that of 1-dim electrons, except that two electrons are allowed to be in one state by Pauli exclusion principle. To elaborate,

##dN=\frac{dk}{\frac{2π}{a}}=\frac{a}{2π}dk## for phonons,

##dN=2⋅\frac{dk}{\frac{2π}{a}}=\frac{a}{π}dk## for electrons.

But in Kittel's solid state physics, the latter is described as a phonon case. What's wrong with my procedure?
 
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cozycoz said:
I'm to get the density of states of 1-dim linear phonons, with N atoms. I think it's a lot similar to that of 1-dim electrons, except that two electrons are allowed to be in one state by Pauli exclusion principle. To elaborate,

##dN=\frac{dk}{\frac{2π}{a}}=\frac{a}{2π}dk## for phonons,

##dN=2⋅\frac{dk}{\frac{2π}{a}}=\frac{a}{π}dk## for electrons.

But in Kittel's solid state physics, the latter is described as a phonon case. What's wrong with my procedure?
Are you sure ? My understanding is that two electrons are not allowed to be in one state by the Pauli exclusion principle
 
Mentz114 said:
Are you sure ? My understanding is that two electrons are not allowed to be in one state by the Pauli exclusion principle
?
I meant two electrons with two different spin types..up and down. That's why we should multiply 2 in electron case. What I calculated by ##\frac{dk}{\frac{2π}{a}}## is spatial part, not including spin part.
 
cozycoz said:
What's wrong with my procedure?
Hard to say if you don't post how you derived the density of states.
 
DrClaude said:
Hard to say if you don't post how you derived the density of states.
okay

I want to get how many phonon states(dN) are in [K, K+dK] in 1d K-space. For a state occupies small length ##\frac{2π}{a}## by periodic boundary condition,
##dN=\frac{dK}{\frac{2π}{a}}##.
 

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