Depth/tank/rate of change problem

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Homework Statement


A conical tank, (with vertex down) is 10 feet across the top and twelve feet deep. If water is flowing into the tank at a rate of 10 cubic feet per minute, find the rate of change of the depth of the water when the water is 8 feet deep.


Homework Equations

? :frown:



The Attempt at a Solution

? :bugeye:
 
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Have you made any attempt to solve this problem at all? Surely, if someone expects you to do this problem, they expect you to know some basic formulas and some concepts of "related rates".

A very relevant equation would be the volume of a cone of radius R and height h. Also, as the water level goes up, both R and h change. Here's my recomendation: draw a picture, a triangle with base (at the top) of length 10ft and altitude (downward) 12 feet. Now draw a horizontal line across the triangle representing the surface of the water. You can get a relation between h and R using "similar triangles". Replace R by that function of h so you have the volume as a function of h only and differentiate to get dV/dt depending on dh/dt.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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