Derivation of Poisson's Equation and Laplace's Equation

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
2 replies · 20K views
MadMike1986
Messages
23
Reaction score
0
Hi,

Can someone point me in the right direction to a derivation of Poisson's Equation and of Laplace's Equation, (from Maxwell's equations I think) both in a vacuum and in material media?

How does one get from Maxwell's equations to Poisson's and Laplace's?
 
Physics news on Phys.org
So the two relevant maxwell's equations are:
[tex]\vec{\nabla} \cdot \vec{E} = \frac{\rho}{\epsilon}[/tex]
[tex]\vec{\nabla} \times \vec{E} = - \frac{\partial \vec{B}}{\partial t}[/tex]

For an electrostatic system, there is no changing B field so,
[tex]\vec{\nabla} \times \vec{E} = 0[/tex]
Which implies E can be written as the gradient of a scalar potential,
[tex]\vec{E} = - \vec{\nabla} \varphi[/tex]

Combining this fact with the first equation,
[tex]\vec{\nabla} \cdot \vec{\nabla} \varphi = \nabla^2 \varphi = - \frac{\rho}{\epsilon}[/tex]

And of course Laplace's equation is the special case where rho is zero.

Cheers!
 
Ah, thank you very much. That's not so bad after all.