Derivation of Poisson's Equation and Laplace's Equation

AI Thread Summary
The discussion focuses on deriving Poisson's and Laplace's equations from Maxwell's equations in both vacuum and material media. It highlights that in electrostatic systems, the changing magnetic field is absent, leading to the conclusion that the electric field can be expressed as the gradient of a scalar potential. By combining this with the divergence of the electric field, the derivation shows that the Laplacian of the potential equals the negative charge density divided by permittivity. Laplace's equation emerges as a special case when the charge density is zero. The conversation concludes with an acknowledgment of the clarity gained from this derivation.
MadMike1986
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Hi,

Can someone point me in the right direction to a derivation of Poisson's Equation and of Laplace's Equation, (from Maxwell's equations I think) both in a vacuum and in material media?

How does one get from Maxwell's equations to Poisson's and Laplace's?
 
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So the two relevant maxwell's equations are:
\vec{\nabla} \cdot \vec{E} = \frac{\rho}{\epsilon}
\vec{\nabla} \times \vec{E} = - \frac{\partial \vec{B}}{\partial t}

For an electrostatic system, there is no changing B field so,
\vec{\nabla} \times \vec{E} = 0
Which implies E can be written as the gradient of a scalar potential,
\vec{E} = - \vec{\nabla} \varphi

Combining this fact with the first equation,
\vec{\nabla} \cdot \vec{\nabla} \varphi = \nabla^2 \varphi = - \frac{\rho}{\epsilon}

And of course Laplace's equation is the special case where rho is zero.

Cheers!
 
Ah, thank you very much. That's not so bad after all.
 
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