Derivation of the Equilibrium Constant

AI Thread Summary
The discussion centers on understanding the derivation of the equilibrium constant from Gibbs Free Energy, specifically the equation Σv_jA_j = 0. The main points of confusion involve the meaning of this summation, which is related to mass conservation in a chemical reaction. Participants clarify that the equation accounts for the stoichiometry of reactants and products, where the coefficients of products are considered negative to ensure the total sums to zero, reflecting conservation of mass. There is also a question about why the summation appears to only go up to n, with some clarification that it actually sums over all species involved in the reaction, not just up to n. The conversation highlights the importance of understanding the stoichiometric coefficients in the context of chemical equilibrium.
gsingh2011
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I'm trying to understand this: http://en.wikipedia.org/wiki/Equilibrium_constant#Derivation_from_Gibbs_Free_Energy
And there are few steps that I don't get. My first question is probably a stupid one, but where does the \Sigmav_{j}A_{j}=0 come from? What exactly is it summing up, the number of atoms? Are you assuming that the products side is negative? (Because I don't see how else you would get zero) And why does it only go up to n?

I'll ask my other questions after I get some replies because it's possible I'll figure them out after I read the replies.
 
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gsingh2011 said:
where does the \Sigmav_{j}A_{j}=0 come from? What exactly is it summing up, the number of atoms? Are you assuming that the products side is negative? (Because I don't see how else you would get zero) And why does it only go up to n?

My guess is it is just a mass conservation, and yes, products are negative.
 
Borek said:
My guess is it is just a mass conservation, and yes, products are negative.

Ok, but why does it only sum up to n? The first equation in the derivation shows the first product being n but then shows more products after that. If it was mass conservation, wouldn't it have to sum passed n?
 
Where does it sum only to n? It sums for all j.
 
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