- #1

CalculusHelp1

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## Homework Statement

The problem:

Find the derivative of

x

^{2}multiplied by the integral of dt/(t-2t

^{2}) from x to -x

^{2}+2x

i.e, the function is x^2 times integral of [1/(t-2t^2)]dt from a to b with a being x and b being -x^2+2x

## Homework Equations

Derivative and integral definitions

## The Attempt at a Solution

Without the x^2 in front of the integral I think I can handle this question. I believe it would just be the function inside of the integral [1/(x-2x^x)] multiplied by -2x +2 (which is the derivative of the upper limit). Am I on the right track? If so, how do you handle the multiplier in front of the integral?