Find the derivative of
x2 multiplied by the integral of dt/(t-2t2) from x to -x2+2x
i.e, the function is x^2 times integral of [1/(t-2t^2)]dt from a to b with a being x and b being -x^2+2x
Derivative and integral definitions
The Attempt at a Solution
Without the x^2 in front of the integral I think I can handle this question. I believe it would just be the function inside of the integral [1/(x-2x^x)] multiplied by -2x +2 (which is the derivative of the upper limit). Am I on the right track? If so, how do you handle the multiplier in front of the integral?