Derivative of e^x=e^x, the derivative of e^2x doesn't equal e^2x

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I have a test tomorrow so I may keep asking questions frequently. For now, why is it that when the derivative of e^x=e^x, the derivative of e^2x doesn't equal e^2x. I've been looking for the rule but can't find it anywhere.
 
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Use the chain rule.
 
derivative of
e^x = (1)(e^x)
the 1 comes from the derivative of x because of chain rule

derivative of
e^2x = (2)(e^2x)
the 2 comes from the derivative of 2x because of chain rule

correct me if i am wrong.
 
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thanx, makes much more sense
 
learn this rule: d/dx(e^u) = e^u (du/dx)
 
e^{2x}=[e^x]^2
Since \frac{d}{dx}f(x)^n = nf'(x){f(x)}^{n-1}
then if f(x)=e^{2x} ...go from there.
 
That's again the chain rule but with the two functions reversed!
 
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