Riles246
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Homework Statement
d/dT (e-E0/(kT))
Homework Equations
d/dx(ex) = ex
The Attempt at a Solution
e-E0/(kT) * E0/kT2 ?
Do you use the chain rule on the exponent of e?
The discussion focuses on differentiating the exponential function e^(-E0/(kT)) with respect to T. The correct approach involves applying the chain rule, as confirmed by multiple participants. The derivative is expressed as e^(-E0/(kT)) * (E0/(kT^2)). The chain rule is essential for handling the exponent in this context, ensuring accurate differentiation of functions involving exponential terms.
PREREQUISITESStudents in calculus, physics, or engineering fields, particularly those studying thermodynamics or exponential functions in mathematical contexts.
Looks spot on to meRiles246 said:Homework Statement
d/dT (e-E0/(kT))
Homework Equations
d/dx(ex) = ex
The Attempt at a Solution
e-E0/(kT) * E0/kT2 ?
Do you use the chain rule on the exponent of e?
. And yes, you would use the chain rule (followed by the power rule on the exponent) to differentiate the function.