Derivative of exponential functions

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SUMMARY

The discussion focuses on differentiating the exponential function e^(-E0/(kT)) with respect to T. The correct approach involves applying the chain rule, as confirmed by multiple participants. The derivative is expressed as e^(-E0/(kT)) * (E0/(kT^2)). The chain rule is essential for handling the exponent in this context, ensuring accurate differentiation of functions involving exponential terms.

PREREQUISITES
  • Understanding of calculus, specifically differentiation techniques.
  • Familiarity with exponential functions and their properties.
  • Knowledge of the chain rule and power rule in calculus.
  • Basic concepts of thermodynamics, particularly the variables E0, k, and T.
NEXT STEPS
  • Study the application of the chain rule in calculus.
  • Learn about differentiating exponential functions in depth.
  • Explore thermodynamic equations involving E0, k, and T.
  • Practice solving similar differentiation problems involving exponential functions.
USEFUL FOR

Students in calculus, physics, or engineering fields, particularly those studying thermodynamics or exponential functions in mathematical contexts.

Riles246
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Homework Statement



d/dT (e-E0/(kT))

Homework Equations



d/dx(ex) = ex

The Attempt at a Solution



e-E0/(kT) * E0/kT2 ?

Do you use the chain rule on the exponent of e?
 
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Riles246 said:

Homework Statement



d/dT (e-E0/(kT))

Homework Equations



d/dx(ex) = ex

The Attempt at a Solution



e-E0/(kT) * E0/kT2 ?

Do you use the chain rule on the exponent of e?
Looks spot on to me :approve:. And yes, you would use the chain rule (followed by the power rule on the exponent) to differentiate the function.
 
if u=u(x),
d/dx (e^u) = e^u du/dx
d/dx (e^(1/x)) = e^(1/x) (-1)/(x^2)
d/dx (e^(a/x)) = e^(a/x) (-a)/(x^2)
d/dx (e^(a/bx)) = e^(a/bx) (-a/b)/(x^2)
 

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