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## Homework Statement

Find derivative of tan[itex]^{-1}[/itex]([itex]\frac{3sinx}{4+5cosx}[/itex])

## Homework Equations

deriviative of tan[itex]^{-1}[/itex]=[itex]\frac{U'}{1+U^{2}}[/itex]

## The Attempt at a Solution

I found U'= [itex]\frac{12cosx+15}{(4+5cosx)^{2}}[/itex]

1+U[itex]^{2}[/itex]=1+[itex]\frac{9sin^{2}x}{(4+5cosx)^{2}}[/itex]

I think my components are correct but my answer is still incorrect. Are these basic components even correct (if so I can proceed on my own from here)?

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## The Attempt at a Solution

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