Derivative of kinectic energy , dK/dv

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The discussion centers on the relationship between kinetic energy and linear momentum, specifically how the derivative of kinetic energy with respect to velocity results in momentum. Kinetic energy is defined as Ek = 1/2mv², and its derivative with respect to velocity yields mv, which is the expression for linear momentum. Participants highlight the connection between these concepts through Newtonian physics, emphasizing that both are linked to force, as force is the derivative of momentum. The conversation also touches on the implications of these relationships in different inertial frames. Understanding these principles is crucial for grasping fundamental physics concepts.
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i'm in my freshman year and I'm starting to learn Derivatives in Calculus, and I was wondering, once Ek (kinectic energy) = 1/2mv², then, the derivative of Ek in term of velocity would be mv, which is equal to the linear momentum... I'm finding hard to understand the idea that the variation of Kinect over a variable velocity is the linear momentum...can someone explain me this in a didactic way? I was just playing around deriving physics formulas haha
 
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hi c77793! :smile:
c77793 said:
I'm finding hard to understand the idea that the variation of Kinect over a variable velocity is the linear momentum...can someone explain me this in a didactic way?

it's because of Newtonian Relativity

the (Newtonian) laws of physics are the same in any inertial frame​

suppose you have bodies with ∑miui2 = ∑mivi2 in one frame

now choose another frame with relative velocity w in the k-direction …

∑mi(ui - wk).(ui - wk) = ∑mi(vi - wk).(vi - wk)
cancelling (and dividing by 2) gives us …

w∑miui.k = w∑mivi.k

since w is arbitrary, we can divide by w, and get conservation of momentum in in the k direction

however, instead of cancelling, we could have differentiated wrt w (in other words, exploiting the translational symmetry of Newtonian space), giving …

w∑mi(ui - wk).k = w∑mi(vi - wk).k

(and then cancelled, giving the same result)

(btw, this also works with Einsteinian energy and momentum, in Minkowski space)
 
c77793 said:
i'm in my freshman year and I'm starting to learn Derivatives in Calculus, and I was wondering, once Ek (kinectic energy) = 1/2mv², then, the derivative of Ek in term of velocity would be mv, which is equal to the linear momentum... I'm finding hard to understand the idea that the variation of Kinect over a variable velocity is the linear momentum...can someone explain me this in a didactic way? I was just playing around deriving physics formulas haha

Well I was also wondering about that and I can't still find the physical relationship between the two, however both are related to force (since force is the derivative of momentum and work is (force)(distance)).
The complete derivation you can find in this thread https://www.physicsforums.com/showthread.php?t=68682
 
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