- #1
lionely
- 576
- 2
Homework Statement
If x = asecθ, y =btanθ show that
dy/dx = (b/a) cosecθ and d2y/dx2 = (-b/a2)cot^3θ
The attempt at a solution
I got the 1st part
dy/dx = (dy/dθ) * (dθ/dx) = bsec^2θ x 1/(secθtanθ)= (b/a) cosecθ
Now I tried differentiating a 2nd time and I don't get the answer they want me to get. I
even tried finding d^2y/dθ and dx^2/dθ
then used the chain rule still didn't get it.
Please guide me someone :S