- #1

TommyLF

- 3

- 0

Find the 2nd derivative at the indicated point:

y= x(ln x) At the point (1,0)

I got to:

y''= [tex]

\frac{1}{x}

[/tex]

So do I just sub in 1 for x? And then the answer would be 1?

Also, I need help on the following problem:

Evaluate the first derivative at the given value X: x=0

[4^(3x)(x^3 - x + 1)^(1/5)] (And then all of that raised to the -2)

-------------------------

(x^2 + x + 1)^(4)