Derivatives of Trig with Triangles

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Homework Help Overview

The discussion revolves around finding the rate at which the area of a triangle is decreasing given two sides and the rate of change of the angle between them. The subject area includes derivatives, trigonometry, and geometric properties of triangles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the use of Heron's formula and question its applicability given the known angle. There is a suggestion to express the area as a function of the two sides and the contained angle. Some participants express confusion about the differentiation process and the treatment of constants in derivatives.

Discussion Status

The discussion is ongoing, with participants exploring different methods to approach the problem. Some guidance has been offered regarding expressing the area in terms of the angle, but there is still some confusion about the differentiation process and its implications.

Contextual Notes

Participants are working under the constraints of the problem as posed, including the fixed lengths of the triangle's sides and the rate of change of the angle. There is an acknowledgment of the challenge in applying certain formulas due to the specific information provided.

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[SOLVED] Derivatives of Trig with Triangles

1. Two sides of a triangle are six and eight metres in length. If the angle between them decreases at the rate of 0.035 rad/s, find the rate at which the area is decreasing when the angle between the sides of fixed length is pi/6. Answer 0.727 m^2/min


2. I tried using Heron's formula but I realized it was almost impossible to take the derivative somehoe with the angle needed. My givens are
dtheta/dt = -0.035 rad/s
the angle between them is pi/6 or 30 degrees
Now to find da/dt...


Thanks
 
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I'm not sure why you're using Heron's formula - that looks to be better when you know all three sides and don't necessarily know any of the angles.

Can you express the area as a function of the two fixed lengths and the contained angle? It's pretty simple to take the derivative of the relevant expression.
 
no sry i don't understand how to express the equation but what i think is cut the triangle into two?
 
nvmi got it thank you very much! =) But one thing when u take the derivative of 24sin theta,w hy is it that u leave the 24?
 
I'm not sure I understand your question. It's just:

d/dt (k*f(t)) = k* df/dt , k = constant

Is that clear?
 

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