Derive Equation for Velocity as Function of Time - Help Integrating

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The discussion focuses on deriving an equation for an object's velocity as a function of time, starting from the acceleration equation a = -(kvo/m). The user attempts to integrate the equation, leading to the relation 1/v = -kt/m + C, and expresses concern about the correctness of their steps. They recognize that the integral of dv/v results in the natural logarithm, ultimately arriving at v = e^(-kt/m + C). Additionally, the context of the equation relates to rocket motion, where mass varies with time, and emphasizes that velocity can be expressed in terms of mass rather than time. The conversation highlights the importance of unit consistency in the derived equations.
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Homework Statement


Derive an equation for an objects velocity as a function of time


Homework Equations



i have that a=-(kvo/m)

The Attempt at a Solution


so i get dv/v=-(k/m)dt then i get
1/v= -kt/m +C and then I am stuck
 
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It's been awhile, but I think the integral of dv/v is the natural log of v. Then you can probably exponentiate both sides
 
so
lnv= ln(-kt/m +C)
then
e^lnv=e^ln(-kt/m +C)
so is this right
v=e^ln(-kt/m +C)
 
you only have the 1/v on the left side:

lnv= (-kt/m +C)

e^lnv=e^(-kt/m +C)
so is this right
v=e^(-kt/m +C)

yeah, that seems about right. I'm a little worried about the units, maybe you can do something with that k or C...
 
a=-(kvo/m)
The above relation represent rocket equation where vo represents the velocity of escaping of gas which is constant an k represents dm/dt, the mass of fuel ejected per unit time. It is also constant. Here mass of the fuel is varying with time.
So you can find the velocity of the object with respect to mass rather than the time.
a = dv/dt = - (dm/dt)vo/m
dv = -vo(dm/m). To find the velocity take the integration between the limits m = Mo to m = M.
 
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