Derive Radiation Pressure in terms of N, V, hf

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SUMMARY

The discussion focuses on deriving the radiation pressure exerted by a gas of photons using kinetic theory. The pressure is expressed as P = (1/3)h(f^2)λ(N/V)(1/c), where N represents the number of photons, V is the volume, and hf is the energy of each photon. The momentum transferred to the wall by the photons is calculated as 2(hf/c), and the number of collisions is determined using the relationship between wavelength and frequency. The challenge lies in expressing the final result in terms of the product hf.

PREREQUISITES
  • Kinetic theory of gases
  • Photon momentum and energy relationships
  • Basic principles of pressure and force
  • Understanding of wave-particle duality
NEXT STEPS
  • Study the derivation of pressure in thermodynamics
  • Learn about photon interactions with matter
  • Explore the concept of radiation pressure in astrophysics
  • Investigate the implications of the equation P = (1/3)h(f^2)λ(N/V)(1/c)
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Students and researchers in physics, particularly those focusing on thermodynamics, quantum mechanics, and astrophysics, will benefit from this discussion.

duran9987
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Homework Statement


Compute the radiation pressure exerted by a gas of photons (according to kinetic theory). There are N photons, each with energy hf, the momentum is hf/c, and the walls are perfectly reflecting. Express the pressure in terms of N, V, and the product hf.

Homework Equations


Pressure = (1/3)*(Nk/V) (mv^2) , where v^2 is an average
Pressure = Force / Area
Speed of Photons = λf
Force on Area A = (Number of collisions on the wall in time Δt)(Momentum transferred to the wall per collision)/(Δt)

The Attempt at a Solution


The momentum transferred to the wall by the photons is 2(hf/c)
The number of collisions = ((λf)ΔtA)(1/2)(N/V)
Force on Area A = (hf/c)(A)(N/V)(λf)
Multiply both Sides by Area to get pressure = P = (1/3)h(f^2)λ(N/V)(1/c)

Not sure how to express it in terms of the product hf.
 
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Use c=λf from the relevant equations?
 

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