Deriving Equations for Light Sphere in Collinear Motion - O and O' Observers

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The discussion centers on deriving equations for a light sphere emitted by a moving observer O' in collinear motion relative to a stationary observer O. The equations governing the light sphere are established as ct' = ± x' for O' and x^2 + y^2 + z^2 = (ct)^2 for O. The Lorentz transformations are utilized to relate the coordinates and proper time between the two observers, specifically t' = (t - vx/c^2)λ and x' = (x - vt)λ. The conversation emphasizes the non-simultaneity of events in different frames, asserting that simultaneity in one frame does not translate to the other when relative motion is present.

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  • #571
cfrogue said:
LT already handles time dilation for one event point.

In my view, you apply time dilation for elapsed time differentials for the start and stop points to a time interval in a frame. It has nothing to do with events in the general sense. Sure, events may trigger the stop of the watch or start, but teim dilation applies in general to generic time intervals.
But as I pointed out in an earlier post, if you pick two times (not events) t0 and t1 in a given frame O, there is no unique answer to how long this interval lasted in another frame O', since if you pick one pair of events A and B that occurred at t0 and t1 in O, and another pair of events C and D that also occurred at t0 and t1 in O (so in O the time interval between A and B is obviously the same as the time interval between C and D ), then in frame O' the time interval between A and B can be different than the time interval between C and D. Assuming you don't disagree with this, how do you propose to define the "length of this time interval" in O' such that there is a unique answer?
 
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  • #572
OK, I have the light sphere in O' working correctly.

In section 3, Einstein said the following.

At the time t = τ = 0, when the origin of the co-ordinates is common to the two systems, let a spherical wave be emitted therefrom, and be propagated with the velocity c in system K. If (x, y, z) be a point just attained by this wave, then

x²+y²+z²=c²t².
Transforming this equation with the aid of our equations of transformation we obtain after a simple calculation

x'² + y'² + z'² = τ²c²
The wave under consideration is therefore no less a spherical wave with velocity of propagation c when viewed in the moving system. This shows that our two fundamental principles are compatible.5

http://www.fourmilab.ch/etexts/einstein/specrel/www/


It has to be done just like the above, point by point.

It is false that

ct' = ±x'.

Normally we think of a light sphere this way, but this cannot work under LT.

Each point is LT transformed from O to O' and then the radius for the sphere in O' comes out correctly because of the t' adjustment for each direction of the light ray.
 
  • #573
JesseM said:
But as I pointed out in an earlier post, if you pick two times (not events) t0 and t1 in a given frame O, there is no unique answer to how long this interval lasted in another frame O', since if you pick one pair of events A and B that occurred at t0 and t1 in O, and another pair of events C and D that also occurred at t0 and t1 in O (so in O the time interval between A and B is obviously the same as the time interval between C and D ), then in frame O' the time interval between A and B can be different than the time interval between C and D. Assuming you don't disagree with this, how do you propose to define the "length of this time interval" in O' such that there is a unique answer?

Simple, use the universal constant

t' = r/c.

Now bring this back to O.
 
  • #574
cfrogue said:
Simple, use the universal constant

t' = r/c.

Now bring this back to O.
I don't understand your response at all. If I pick a pair of times t0 and t1 in O, so the time interval's size in O is (t1 - t0), can you show me how the above comment is supposed to apply to calculating the time interval in O'? In other words, show me the actual equations used in the derivation which will end up yielding a final equation for the time interval in O'.

Also, what does r represent here? Is it the radius of the light sphere in O' at time t' in O'?
 
  • #575
cfrogue said:
OK, I have the light sphere in O' working correctly.

In section 3, Einstein said the following.

At the time t = τ = 0, when the origin of the co-ordinates is common to the two systems, let a spherical wave be emitted therefrom, and be propagated with the velocity c in system K. If (x, y, z) be a point just attained by this wave, then

x²+y²+z²=c²t².
Transforming this equation with the aid of our equations of transformation we obtain after a simple calculation

x'² + y'² + z'² = τ²c²
The wave under consideration is therefore no less a spherical wave with velocity of propagation c when viewed in the moving system. This shows that our two fundamental principles are compatible.5

http://www.fourmilab.ch/etexts/einstein/specrel/www/


It has to be done just like the above, point by point.

It is false that

ct' = ±x'.
Why do you say it's false? If we set y and z to zero (so we're only looking at where the light is on the x-axis), then x'² + y'² + z'² = t'²c² reduces to t'²c² = x'² which is the same as ct' = ±x'.
 
  • #576
JesseM said:
I don't understand your response at all. If I pick a pair of times t0 and t1 in O, so the time interval's size in O is (t1 - t0), can you show me how the above comment is supposed to apply to calculating the time interval in O'? In other words, show me the actual equations used in the derivation which will end up yielding a final equation for the time interval in O'.

Also, what does r represent here? Is it the radius of the light sphere in O' at time t' in O'?

Oh, that is the time the light sphere strikes all points.

The rest radius is r in O', c is constant, thus t' = c/r.

The emission of light is t0=0 and the termination of the interval is t1=c/r.

Note I am not picking a light event as the termination point. It is an elapsed time.
 
  • #577
JesseM said:
Why do you say it's false? If we set y and z to zero (so we're only looking at where the light is on the x-axis), then x'² + y'² + z'² = t'²c² reduces to t'²c² = x'² which is the same as ct' = ±x'.

Because we proved there exists two different t's in O such that ct' = ±x' is satisified and this violates logical consistency.

So, I am saying that is not the way to approach the SR light sphere.

If it is approached as t increases and each point is transformed to satisfy,
x'² + y'² + z'² = τ²c²
then we have logical consistency.

On the other hand, if we include ±x', we get different length radii for each directiion due to the simultaneity difference in each direction of the light ray in O.

It can only be approached as taking each spacetime coord in O and LT'ing it, then applying
x'² + y'² + z'² = τ²c²


That is why I say the normal logic of ct' = ±x' does not work.

The following points in O satisify that condition

t1=r/(λ(c-v)) for the ray point right and
t2=r/(λ(c+v)) for the ray point left.

If you run these through LT with x=+ct and x=-ct as appropriate, you will find two different satisfactions of the equation ct' = ±x' at two different times in O which creates two different light spheres which is a logical inconsistancy.
 
  • #578
I have concluded LT will not give me the center of the light sphere after and time t in the frame of O.

I realize Einstein assumed it is at vt.

Does anyone have anything else on this that I am not seeing?
 
  • #579
Also, if you run this point through LT,

x = λvt/(1+λ)

t' = t( t - vx/c² )λ

You will find t' = t with collinear relative motion.

Thus, we must be very careful not to conclude LT decides time dilation between frames.
 
  • #580
cfrogue said:
Because we proved there exists two different t's in O such that ct' = ±x' is satisified and this violates logical consistency.
What violates logical consistency? I don't see anything illogical about the fact that there can be two events with values of (x,t) that satisfy ct = ±x, and with t being different for each event, such that when you apply the Lorentz transformation to the (x,t) coordinates of each event to get the (x',t') coordinates of the same event, then both events can have (x',t') coordinates that satisfy ct' = ±x' but with the new feature that the t' coordinate is the same for each event. Are you saying this is illogical or impossible?
cfrogue said:
That is why I say the normal logic of ct' = ±x' does not work.

The following points in O satisify that condition

t1=r/(λ(c-v)) for the ray point right and
t2=r/(λ(c+v)) for the ray point left.

If you run these through LT with x=+ct and x=-ct as appropriate, you will find two different satisfactions of the equation ct' = ±x' at two different times in O which creates two different light spheres which is a logical inconsistancy.
Again, what's a logical inconsistency? These events occur at different times in O, so naturally they are part of two different light spheres at different times in O. The equation ct = ±x was never supposed to define a single light sphere, rather it is an equation defining all points that lie on the light cone in 1D, it can include events at different times in O. Exactly the same is true of the equation x'² + y'² + z'² = τ²c², τ is a variable so this too is the 3D version of a light cone which includes events that lie on the path of the light at different times in O.
 
  • #581
cfrogue said:
I have concluded LT will not give me the center of the light sphere after and time t in the frame of O.

I realize Einstein assumed it is at vt.
Why have you concluded that? The center of the light sphere in O' is always at x'=0, and if you apply Lorentz transformation to some event which has an x' coordinate of 0 you'll always get an event whose x and t coordinates satisfy x=vt. Do you disagree? If not, what's the problem?
 
  • #582
JesseM said:
Why have you concluded that? The center of the light sphere in O' is always at x'=0, and if you apply Lorentz transformation to some event which has an x' coordinate of 0 you'll always get an event whose x and t coordinates satisfy x=vt. Do you disagree? If not, what's the problem?

I get x=(vt)λ
 
  • #583
cfrogue said:
I get x=(vt)λ
Suppose the event has coordinates x'=0, t'=T' in O'. Then the coordinates in O are:

x = gamma*(x' + vt') = gamma*vT'
t = gamma*(t' + vx'/c^2) = gamma*T'

So, x/t = (gamma*vT')/(gamma*T') = v, and if x/t=v then x=vt.
 
  • #584
Originally Posted by cfrogue
Because we proved there exists two different t's in O such that ct' = ±x' is satisified and this violates logical consistency.

JesseM said:
What violates logical consistency? I don't see anything illogical about the fact that there can be two events with values of (x,t) that satisfy ct = ±x, and with t being different for each event, such that when you apply the Lorentz transformation to the (x,t) coordinates of each event to get the (x',t') coordinates of the same event, then both events can have (x',t') coordinates that satisfy ct' = ±x' but with the new feature that the t' coordinate is the same for each event. Are you saying this is illogical or impossible?

No, I am saying uisng that method creates two different light spheres. I gave you the points. Use them and apply the radius in both directions.

JesseM said:
[
Again, what's a logical inconsistency? These events occur at different times in O, so naturally they are part of two different light spheres at different times in O. The equation ct = ±x was never supposed to define a single light sphere, rather it is an equation defining all points that lie on the light cone in 1D, it can include events at different times in O. Exactly the same is true of the equation x'² + y'² + z'² = τ²c², τ is a variable so this too is the 3D version of a light cone which includes events that lie on the path of the light at different times in O.

I have been down this road.

It does not achieve anything. I created two different light spheres in O' because of the simultaneity differential of the direction of the light rays in O.

Yet, if I do strictly point by point transforms as suggested by Einstein, I have a consistency resolution.
 
  • #585
JesseM said:
Suppose the event has coordinates x'=0, t'=T' in O'. Then the coordinates in O are:

x = gamma*(x' + vt') = gamma*vT'
t = gamma*(t' + vx'/c^2) = gamma*T'

So, x/t = (gamma*vT')/(gamma*T') = v, and if x/t=v then x=vt.

Good one.

Thanks. That works.
 
  • #586
cfrogue said:
I clearly see a difference of when an event will occur concerning light and time dilation.
Obviously. Time dilation requires Δx=0 and Δx never equals 0 for light, so there will always be a difference.
cfrogue said:
It is false that

ct' = ±x'
You already agreed it was true, and it was proved conclusively several different ways. If you want to suddenly go back and ignore the previous 570 posts then I am done with this. What is the point of continuing the conversation if you will just ignore that amount of proof?
 
  • #587
cfrogue said:
Yet, if I do strictly point by point transforms as suggested by Einstein, I have a consistent resolution.

Yes, that is the only way to do it, and that is what I've been doing all along, although that was not apparent to you. Regardless, this is correct, and fundamental.
 
  • #588
DaleSpam said:
Obviously. Time dilation requires Δx=0 and Δx never equals 0 for light, so there will always be a difference.
You already agreed it was true, and it was proved conclusively several different ways. If you want to suddenly go back and ignore the previous 570 posts then I am done with this. What is the point of continuing the conversation if you will just ignore that amount of proof?

I am the one that introduced ct' = +-x'.

That was my argument.

You did not prove anything to me about this.

Then, I discovered it created two light spheres. You agreed.

The question for you is how do you create logical consistency with ct' = +-x'?

I would like to see this.
 
  • #589
atyy said:
Yes, that is the only way to do it, and that is what I've been doing all along, although that was not apparent to you. Regardless, this is correct, and fundamental.

Agreed.
 
  • #590
atyy said:
Yes, that is the only way to do it, and that is what I've been doing all along, although that was not apparent to you. Regardless, this is correct, and fundamental.

Well, you could be more specific.

http://www.youtube.com/watch?v=N9QosirK-Gw"
 
Last edited by a moderator:
  • #591
cfrogue said:
The question for you is how do you create logical consistency with ct' = +-x'?

I would like to see this.
We already demonstrated this more than 500 posts ago. If you would like to see it just use your browser to review the thread.
 
  • #592
cfrogue said:
That is why I say the normal logic of ct' = ±x' does not work.

The following points in O satisify that condition

t1=r/(λ(c-v)) for the ray point right and
t2=r/(λ(c+v)) for the ray point left.

If you run these through LT with x=+ct and x=-ct as appropriate, you will find two different satisfactions of the equation ct' = ±x' at two different times in O which creates two different light spheres which is a logical inconsistancy.

Yes, these imply that there are two light spheres in O at two different times. But that is not a problem, since there are an infinite number of light spheres in O, one for each t.

Thus t1=r/(λ(c-v)), x1R=ct1 is one side of the light sphere in O at t1, whose other side must be t1=r/(λ(c-v)), x1L=-ct1, which by the LT you can check does lie on a light sphere of O'.

Smilarly, t2=r/(λ(c+v)), x2L=-ct2 is one side of the light sphere in O at t2, whose other side must be t2=r/(λ(c+v)), x2R=ct2, which by the LT you can check does lie on a light sphere of O'.
 
  • #593
With 592 posts plus this one, this thread has by far the most posts of any thread in the Relativity forum, ever. It's long overdue time to give it a rest. Thread closed.
 

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