Deriving F=a2/λL in Fresnel Diffraction

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SUMMARY

The derivation of F=a²/λL in Fresnel diffraction is established through the relationship L=1/z+1/z', where z represents the distances from the slit to the observation point. The discussion highlights the approximation Δ = R - √(R² - a²) leading to Δ ≈ a²/(2R) under the condition that the wavefront is plane. This approximation is valid in the Fresnel regime, where R is approximately equal to a²/λ. The insights provided clarify the transition from the Fraunhofer to the Fresnel regime in wave optics.

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khanley
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Hi guys,

I can't find my notes on Fresnel diffraction and I have my Optics exam on Monday...

Does anyone know how to derive F=a2/λL where L=1/z+1/z'

I've googled it to death, checked here and tried in Optics 4th edition by Hecht with no luck...

I'd really appreciate any help.

Thank you so much!
 
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I'll give it a try, but its only an approximate derivation. Maybe it will point you in the correct direction: So we are looking at a slit of width 2a, and a point source S placed some distance behind it. The distance from S to the upper/lower part of the slit we denote R.

The distance between the opening and R we denote Δ, and is the difference between the plane wavefront to the curved wavefront. We find

<br /> \Delta = R-\sqrt{R^2-a^2} = R-R\sqrt{1-\frac{a^2}{R^2}}\approx \frac{a^2}{2R}<br />

If the wavefront is plane we must have Δ<<λ so R >> a2/λ. This is the Fraunhofer regime, so the Fresnel regime is R ~ a2/λ.

I hope it helps.
 

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