Learning DEs: Solving 2nd Order Differential Equations

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SUMMARY

The discussion focuses on solving second-order differential equations (DEs) using Newton's second law of motion, specifically the equation \(x''=\frac{F}{m}\). The user seeks clarification on deriving the equation of motion \(x(t)=\frac{F}{2m}t^2+vt+x\) from this DE. The solution involves integrating the equation twice, which simplifies the process significantly compared to the more complex methods typically found in textbooks. This straightforward approach is effective for beginners tackling second-order DEs.

PREREQUISITES
  • Understanding of second-order differential equations
  • Familiarity with Newton's laws of motion
  • Basic integration techniques
  • Knowledge of homogeneous differential equations
NEXT STEPS
  • Study the derivation of equations of motion from differential equations
  • Learn about non-homogeneous second-order differential equations
  • Explore applications of differential equations in physics
  • Practice solving various forms of second-order DEs
USEFUL FOR

Students and self-learners in physics and mathematics, particularly those interested in understanding and solving second-order differential equations.

greg_rack
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Hi guys,

I have just started studying DEs on my own, so pardonne moi in advance for the probably silly question :)

Via Newton's second law of motion:
$$x''=\frac{F}{m} \ [1]$$
Which is a second-order differential equation.
But, from here, how do I get the good old equation of motion:
$$x(t)=\frac{F}{2m}t^2+vt+x$$
by solving the DE? What is the procedure to apply? In my textbook, only second-order homogeneous DE are treated, but nothing with the form of ##[1]##... and online everything looks over-complicated.
 
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Ok, I managed to get to the solution just by integrating twice both sides.
I was wrapping my head for nothing!
 
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