Describing Electronic orbit in 3D space using A matrix.

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The discussion focuses on plotting the trajectory of an imaginary electron in 3D space and representing its points using a specific matrix A. The user seeks guidance on how to further develop their model and is new to matrices, looking for resources to create and visualize 3D objects. Suggestions include starting with a position vector in the x-y plane and using a 2x2 matrix for transformations to simulate circular motion. The conversation emphasizes the importance of understanding matrix operations to effectively model the electron's orbit. Overall, the user is encouraged to explore matrix multiplication techniques for 3D modeling.
kenneththo85431
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I've plotted out the trajectory of an imaginary electron in 3D; next I represent it's points with the matrix A(x1 y1 z1) "throughout it's orbit":
( -1/2 -1 1
( -2 -1.5 2
(-1/2 2 3
( 1 3 1 )
2 -2 -1

Any pointers on where to go from here would be greatly appreciated. External links are helpful too.
 
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You'll have to tell us more. What are you trying to do here? What problem are you trying to solve? How did you come up with these four positions?
 
Yes, I'm new to matrices and I am looking for resources to create objects in 3 dimensions then model those objects in 3 dimensions.
 
kenneththo85431 said:
I've plotted out the trajectory of an imaginary electron in 3D; next I represent it's points with the matrix A(x1 y1 z1) "throughout it's orbit":
( -1/2 -1 1
( -2 -1.5 2
(-1/2 2 3
( 1 3 1 )
2 -2 -1

Any pointers on where to go from here would be greatly appreciated. External links are helpful too.
One way to do this is to start with a position vector in the x-y plane ##\vec{x}=(x,y)## and use a 2x2 matrix to change the position by multiplication so that ##\vec{x}_{n+1}=M\vec{x}_n##,

For instance
<br /> M= \pmatrix{\cos\left( a\right) &amp; \sin\left( a\right) \cr -\sin\left( a\right) &amp; \cos\left( a\right) }<br />
so that
<br /> M\vec{x}= \pmatrix{\cos\left( a\right) &amp; \sin\left( a\right) \cr -\sin\left( a\right) &amp; \cos\left( a\right) }\vec{x}=\pmatrix{\sin\left( a\right) \,y+\cos\left( a\right) \,x\cr \cos\left( a\right) \,y-\sin\left( a\right) \,x}<br />
If you start with position (-1,0) and choose a small ##a##, say 0.05 radians, then applying the matrix successively moves the point in a circle with radius 1 and center 0.
 
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Mentz114 said:
One way to do this is to start with a position vector in the x-y plane ##\vec{x}=(x,y)## and use a 2x2 matrix to change the position by multiplication so that ##\vec{x}_{n+1}=M\vec{x}_n##,

For instance
<br /> M= \pmatrix{\cos\left( a\right) &amp; \sin\left( a\right) \cr -\sin\left( a\right) &amp; \cos\left( a\right) }<br />
so that
<br /> M\vec{x}= \pmatrix{\cos\left( a\right) &amp; \sin\left( a\right) \cr -\sin\left( a\right) &amp; \cos\left( a\right) }\vec{x}=\pmatrix{\sin\left( a\right) \,y+\cos\left( a\right) \,x\cr \cos\left( a\right) \,y-\sin\left( a\right) \,x}<br />
If you start with position (-1,0) and choose a small ##a##, say 0.05 radians, then applying the matrix successively moves the point in a circle with radius 1 and center 0.
Wow! Thank you so much!
 

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