Description of Adiabatic Expansion

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
8 replies · 2K views
I_laff
Messages
41
Reaction score
2
I've seen the derivation for the adiabatic expansion of an ideal gas which gives the result ## TV^{\gamma - 1} = constant ## which I understand. I have also seen the a similar result, ## pV^{\gamma} = constant ##. But I can't see how to get from the first expression to the second. Any ideas?
 
Physics news on Phys.org
From doing that you get ## pV^{\gamma} = R(constant) ##. So you just define a new constant on the RHS that contains ## R ##?
 
sophiecentaur said:
Isn't this a straightforward bit of Text Book derivation? Do you not have access to one?
You are probably right, however I don't have a textbook on thermodynamics. I thought of substituting ## \frac{pV}{nR} ## but didn't see how to remove ## nR ## from the final expression. Since they're constant, I guess it's obvious the new constant contains these terms.
 
sophiecentaur said:
If you don't have a textbook, try the Hyperphysics website. They have a fair amount of stuff on the gas laws.
Thanks, I'll check it out :thumbup:.