Design a PID Controller for System G(s) w/ 0% Overshoot & <1s Settling Time

Click For Summary
SUMMARY

The discussion focuses on designing a PID controller for the system G(s) = 1/(10s² + 5s + 10) to achieve a 0% overshoot and a settling time of less than 1 second. Participants emphasize the necessity of critically damped systems (ζ = 1) and suggest placing poles at -5 and -7. However, the initial attempts with a PD controller resulted in a 12.5% overshoot, indicating an under-damped response. Recommendations include starting with a PI controller and using the Ziegler-Nichols method for PID tuning to meet the specified performance criteria.

PREREQUISITES
  • Understanding of PID controller design principles
  • Knowledge of system dynamics and transfer functions
  • Familiarity with Ziegler-Nichols PID tuning method
  • Basic concepts of damping ratios and pole placement
NEXT STEPS
  • Research the Ziegler-Nichols method for PID controller tuning
  • Explore critically damped systems and their characteristics
  • Learn about the effects of zeros on system response
  • Investigate alternative controller designs, such as PI and PID, for specific performance requirements
USEFUL FOR

Control system engineers, students studying control theory, and practitioners involved in PID controller design and tuning.

215
Messages
39
Reaction score
0

Homework Statement


Design a controller for the system G(S) such, that the step response to close loop transfer function has an overshoot of 0% and a settling time of less than 1 sec.

Homework Equations


G(s) = \frac{1}{10s^2 + 5s + 10}
Controller has to be a PID controller.

The Attempt at a Solution


First as the assignment mentions, the overshoot has to be 0% which means that we interested in a critical damped system ζ = 1
since the settling time has to be lower than 1 sec, i can deduce that ωn has to be less than 4. which means that, my poles shall be on the real axis and less than -4.

I chose i want my poles to be at -5 and -7, and using solve i am able to see that a PD controller consiting of d = 115 and p = 340 would do the job.
but the step reponse is showing my about 12.5 percent overshoot, but the settling time matches. the close loop transfer function i end up with
G(s) = \frac{115s + 340}{10s^2 + 120s + 350}
the poles are places where they should be.. so really don't see where i am going wrong with this ? please help my.
 
Last edited:
Physics news on Phys.org
You need some I in order to creep up on the boundary.

Try for a solution with just PI; your initial goal is to satisfy the 0% overshoot requirement.

Then start adding in some D to reduce the total time.
 
215 said:


I chose i want my poles to be at -5 and -7, and using solve i am able to see that a PD controller consiting of d = 115 and p = 340 would do the job.
but the step reponse is showing my about 12.5 percent overshoot, but the settling time matches.


Having poles at -5 and -7 would result in an overdamped system. To have a critically damped system you want matching poles ie. 2 poles at -5.

The fact that your system is under-damped (overshoot), indicates that your poles have imaginary components to them and something is wrong with your solve function.
 
Yes.. but even for an overdamped system it doesn't resemble the charateristica of an overdamped system...
In[959]:= Solve[10 x^2 + 120 x + 350 == 0, x]

Out[959]= {{x -> -7}, {x -> -5}}

There is no complex component.
 
If a system has overshoot its poles have an imaginary component to them.

For designing the controller I would follow ultrafastPED's advice. Design a PI controller first then add your d competition.

I would recommend using the Zeigler Nichols PID tuning method as a good starting point
 
I just don't understand how come i canont determine my PID values, from where i want my poles placed..
I've solved ch. eq. for all possible controllers and PD seems to be the only one capable of given me poles at those two locations.
 
ok. If you look at a second order system with one zero, if the zero is equal to or less than the smallest pole, it can begin to dominate the equation. That is where your overshoot is coming from. It is also due to the fact that you are adding a hgih D component. I would recommend using a PI or PID controller.

It is very hard to get a critically damped PD controlled system.
 
how would zero be able to affect a system... as far I've understood is it only the poles which affects the system.
 
In the case of your system there is a zero at -3. Due to the fact that the zero is ~ half that of the smallest pole, it can influence the system response. As the smallest zero approaches the smallest pole, it will have less and less of an effect on the system.

The idea that only poles effect the system is only true assuming a pole is dominant.
 
  • #10
but how come do they affect the system.. mean if a zero is dominant, would it then act as an dominant pole??.. But still the zero does not contain a imaginary part, which still make no sense why it should oscillate, and create overshoot.
 
  • #12
I can see that it changes, but how can i prevent it? i mean shouldn't they have some conditions aswell??
 
  • #13
The zero is created by the D portion of the PD controller. I recommend using a PI or PID controller.
You are almost always going to get an over-damped step response with a PD controller.
 
  • #14
but it's not possible to make one using a PI which have these values.
 
  • #15
Have you tried the Ziegler-Nichols method for PID controller gains determination? You should be able to come up with a pid controller giving you zero overshoot for your plant transfer function.

I don't know if the 1 sec. settling time is reached thereby.
 
  • #16
since this is just trial model it would be possible to do it. but since the real model cannot become marginal stable, is the method unuseable.
 

Similar threads

Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
7K