Designing a Couette Cell - Get the Right Shear Gradient

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SUMMARY

The discussion focuses on the design of a Couette cell, specifically the relationship between the diameters of concentric cylinders and the resulting shear gradient. A rotating cylinder with a diameter of 28.64789 mm and a static cylinder with a diameter of 29.64789 mm achieves a shear gradient of 3000/sec at 1000 RPM. Alternatively, a rotating cylinder with a diameter of 10.0 mm and a static cylinder with a diameter of 11.0 mm reaches the same shear gradient at 2864.789 RPM. The accuracy of these calculations is confirmed, particularly for the second scenario.

PREREQUISITES
  • Understanding of Couette flow dynamics
  • Familiarity with rotational mechanics
  • Knowledge of shear gradient calculations
  • Basic principles of fluid mechanics
NEXT STEPS
  • Research the mathematical derivation of shear gradients in Couette flow
  • Explore the effects of varying cylinder diameters on shear rates
  • Learn about the applications of Couette cells in rheology
  • Investigate the impact of RPM variations on shear gradient outcomes
USEFUL FOR

Researchers in fluid dynamics, engineers designing rheological testing equipment, and students studying fluid mechanics will benefit from this discussion.

J4MacDonald
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I believe I have an understanding of the proper design for a Couette cell. If I am incorrect, please let me know.

Two concentric cylinders, the internal one rotating, the external one static.

1.) If I have a rotating cylinder with a diameter of 28.64789 mm and a static one with a diameter of 29.64789 mm, then 1000 RPM will produce a shear gradient = 3000/sec

2.) If I have a rotating cylinder with a diameter of 10.0 mm and a static one with a diameter of 11.0 mm, then 2864.789 RPM will produce a shear gradient = 3000/sec

Thank you in advance.
 
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J4MacDonald said:
I believe I have an understanding of the proper design for a Couette cell. If I am incorrect, please let me know.

Two concentric cylinders, the internal one rotating, the external one static.

1.) If I have a rotating cylinder with a diameter of 28.64789 mm and a static one with a diameter of 29.64789 mm, then 1000 RPM will produce a shear gradient = 3000/sec

2.) If I have a rotating cylinder with a diameter of 10.0 mm and a static one with a diameter of 11.0 mm, then 2864.789 RPM will produce a shear gradient = 3000/sec

Thank you in advance.
The first answer should be about 1000/sec. The 2nd answer is correct.
 

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