Designing a Pneumatic Arm to Lift 5kg Load 10m

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Discussion Overview

The discussion revolves around the design and calculations necessary for a pneumatic arm intended to lift a 5kg load to a height of 10 meters. Participants explore the required force and pressure calculations, considering factors such as the stroke length of the piston and the necessary acceleration to achieve the desired height.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant states that a 5kg load experiences a gravitational force of 49N, which is the minimum force required to lift it.
  • Another participant emphasizes the need to calculate the acceleration based on the stroke length of the piston, suggesting that this length is a critical factor in determining the necessary force.
  • A participant proposes a stroke length of 300mm and outlines the calculations for the initial velocity needed to reach 10 meters, deriving that velocity as approximately 14 m/s.
  • Further calculations are presented to determine the acceleration required to achieve this velocity, leading to a formula for force based on the chosen stroke length.
  • The final calculation indicates that with a 300mm stroke, the required force would be approximately 1633N.

Areas of Agreement / Disagreement

Participants generally agree on the basic calculations needed to determine the force required to lift the load, but there is no consensus on the optimal stroke length or the implications of varying that length on the overall design.

Contextual Notes

The discussion does not resolve the assumptions regarding the efficiency of the pneumatic system or the practical implications of the calculated forces and velocities.

MadaraUchiha
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Hey
I want to build a pneumatic arm that can throw stuff around (see attachment image).
Before actually ordering the stuff i want help with some calculations.
i want the arm to be able to push 5kg load (rectangular shaped) straight up into air.
the arm/plunger area that makes contact with load = 0.0050m^2
i want this arm to throw the load to atleast 10 metres off the ground.
How much force/pressure would that require ?
 

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A five kilogram load will be pulled by the Earth by 5*9.8=49N of force. So this much is minimum. To throw it 10m high, you need to calculate the acceleration, which requires information on how long the plunger will be in conact with the mass, or, upto what distance. That will be equal to the length of the stroke of the piston which you should decide.
 
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PhysicoRaj said:
A five kilogram load will be pulled by the Earth by 5*9.8=49N of force. So this much is minimum. To throw it 10m high, you need to calculate the acceleration, which requires information on how long the plunger will be in conact with the mass, or, upto what distance. That will be equal to the length of the stroke of the piston which you should decide.

Ill decide that later according to portability and availability of cylinders but let's say the stroke is 300mm.
Then how do we go on about calculating it ?
 
Let me take the stroke to be x.
Now we will calculate the velocity with which it has to be ejected so that it ends up 10m high.
v2=u2-2gh
v is the velocity at 10m so it is = 0
u is what we have to find out.
h=10m
solving for u we get:
u=√2gh
u=√2*9.8*10
u=14ms-1

Now to calculate the acceleration required to produce that initial velocity:
u2=2ax
u is 14
a is what we will find
x is your piston stroke.

Solve for a:
a=u2/2x
a=196/(2*x)
a=98/x

Now the force that causes this acceleration is:
F=ma
F=5*98/x
F=490/x N

Either choose a convinient x value or F value.

Edit: 300mm implies force=1633N.
 
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Got it !
thanks again.
 
Last edited:

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