Designing a Variable Gain Voltage Divider Circuit

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Homework Help Overview

The discussion revolves around designing a variable gain voltage divider circuit using a 100-kOhm potentiometer and external resistances to achieve specific gain ranges. Participants are exploring the principles of voltage dividers and the relationships between resistances in the context of this circuit design problem.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants express uncertainty about how to begin the problem and question the relevance of equations. Some discuss the relationship between the potentiometer and the required resistances, while others explore the implications of varying the wiper position on the output voltage.

Discussion Status

There is ongoing exploration of the voltage divider concept, with some participants attempting to derive relationships between resistances and output voltage. Guidance has been offered regarding evaluating conditions at different wiper positions, but confusion remains regarding the application of specific formulas and the overall setup.

Contextual Notes

Participants note that the problem's wording is unclear and that there is a lack of instructional examples provided by the teacher, contributing to their confusion. Some express that the majority of the class shares similar difficulties with the problem.

VitaX
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Homework Statement



Using a 100-kOhm potentiometer and suitable external resistances, design a voltage divider circuit such that varying the wiper from end to end varies the gain over the range:
a) 0 to 0.75 V/V
b) 0.2 V/V to 1 V/V
c) 0.1 V/V to 0.9 V/V

Homework Equations



Not Sure to be honest

The Attempt at a Solution



I really do not know where to start on this problem at all. I don't think it is as complicated as it seems to be but my professor is absolutely horrid at teaching, and I really have no idea to go about solving this. What equations are relevant here?
 
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The book had this diagram drawn for the answer in the book along with the answers to parts a-c.

[PLAIN]http://img16.imageshack.us/img16/5962/voltagedivider.png

a) R1 = 33.3 k Ohms, R2 = 0
b) R1 = 0, R2 = 25 k Ohms
c) R1 = R2 = 12.5 k Ohms

And I looked at the voltage divider information on that site you linked but I'm still as lost as ever. For one it doesn't look like the picture above. I'm a little lost on how to find R1 and R2 in those equations when I have 2 unknowns and only one equation as well. And what does the 100 K Ohms fit into in those equations? I don't know perhaps I'm missing something here.
 
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Vo/Vi = 1/[1+R1/R2] and I plugged in 3/4 V/V for Vo/Vi and when I solved for the ratio, I got R2/R1 = 3. The answer to part a is R1 = 33.3 k Ohms, but I get R2 = 33.3 k Ohms, since R2 was in the numerator when I solved for the ratio. So basically I just take the 100 K Ohm Potentiometer and divide by the ratio and that gives me the value for the resistor in the numerator? I think I'm on the right track but if someone could point out a mistake or something, it'd make this go easier as I'm just winging it at the moment.
 
The 100K resistance is given by the problem. You are perhaps missing the understanding of how a potentiometer works.

Let's look at question (a) first. Imagine the slider being at the top position, i.e, between R1 and the 100K resistor. Can you find V0 in terms of Vi? Now imagine the slider being all the way to the other end so that R1 and the 100K are on one side of it and R2 on the other. Again can you find V0 in terms of Vi? Note that you have two conditions that should give two equations from which you can find R1 and R2.

Similar reasoning applies to questions (b) and (c).
 
VitaX said:
Vo/Vi = 1/[1+R1/R2] and I plugged in 3/4 V/V for Vo/Vi and when I solved for the ratio, I got R2/R1 = 3.
You need to find Vo/Vi at an "intermediate" position of the slider, i.e. when the resistance is R1+r on one side and (100K-r)+R2 on the other. Then evaluate Vo/Vi when r = 0 (slider all the way up) and r=100K (slider all the way down) and set each result equal to what you want it to be. This will clarify to you what you are doing.
 
I'm still a bit confused here, but I came across this formula. Vo = [kR/R]Vi or Vo = k*Vi. But then according to this, k is that ratio Vo/Vi. I don't even know anymore this book doesn't have k in any of the main equations, that's one reason I'm confused. I see that the position between the wiper and the bottom lead is kR, where k is Vo/Vi and R is the total resistance of that potentiometer. But my problem is understanding where this is useful at in the equation Vo/Vi = 1/[1+R1/R2]. Perhaps I'm understanding you wrong, if I am I apologize, I'm just a little confused at the lack of information to go on in my notes and in the book. Perhaps if someone could write one equation for part a, I might be able to write the other one for part a and go from there.
 
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[PLAIN]http://img705.imageshack.us/img705/5962/voltagedivider.png

Does this drawing make the problem clearer?
 
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VitaX said:
Does this drawing make the problem clearer?
This does not match your original drawing. I believe the drawing below is the one you should work from.
 

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  • #10
too late now I guess, but the majority of the class had no idea how to work this problem. It truly is worded oddly, plus the fact our teacher did no examples on it at all.
 

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