Determination of a set equality from other set equalities

In summary: I'm sure there are students out there who could have done the problem all by themselves without requiring external guidance. I'm just trying to figure where I fall within that category of genius. :-(In summary, the three cases are:A=B if and only if A\cup C=B\cup CA=B if and only if A\cap C=B\cap CA=B if and only if A\cup C=B\cup C and A\cap C=B\cap C.
  • #1
spaghetti3451
1,344
34

Homework Statement



Can you conclude that A = B if we know that

(a) A [itex]\cup[/itex] C = B [itex]\cup[/itex] C

(b) A [itex]\cap[/itex] C = B [itex]\cap[/itex] C

(c) A [itex]\cup[/itex] C = B [itex]\cup[/itex] C and A [itex]\cap[/itex] C = B [itex]\cap[/itex] C

Homework Equations



The Attempt at a Solution



A=B in all three cases, but I can't find a rigorous proof for any of these cases.

Any help would be greatly appreciated.
 
Physics news on Phys.org
  • #2
It doesn't follow that A=B in the first case. It's easy to find a counterexample. What about the other cases?
 
  • #3
Thanks for the hint!

I've come up with these solutions based on your hint.

1. False. Counterexample: If C = ε, where ε is the universal set, then A [itex]\cup[/itex] C = B [itex]\cup[/itex] C implies A [itex]\cup[/itex] ε = B [itex]\cup[/itex] ε, which further implies that ε = ε. Therefore, A and B are allowed to be arbitrary sets and A is not necessarily equal to B.

2. False. Counterexample: If C = ø, where ø is the universal set, then A [itex]\cap[/itex] C = B [itex]\cap[/itex] C implies A [itex]\cap[/itex] ø = B [itex]\cap[/itex] ø, which further implies that ø = ø. Therefore, A and B are allowed to be arbitrary sets and A is not necessarily equal to B.

3. I'm thinking that this is true. It's always easy to find a counterexample than to find a rigorous proof for a general theorem. It would be nice if you supply a clue.
 
Last edited:
  • #4
As usual, show that A is a subset of B and B is a subset of A.
 
  • #5
Thanks for the hint.

My lecturer assigned this problem as homework and I have not been able to do it without your help. What I mean that I required external guidance. Do you think that this is a sign that my intellectual capacity is not adequate to tackle these sorts of questions?

I'm sure there are students out there who could have done the problem all by themselves without requiring external guidance. I'm just trying to figure where I fall within that category of genius. :-(
 
  • #6
failexam said:
Thanks for the hint.

My lecturer assigned this problem as homework and I have not been able to do it without your help. What I mean that I required external guidance. Do you think that this is a sign that my intellectual capacity is not adequate to tackle these sorts of questions?

I'm sure there are students out there who could have done the problem all by themselves without requiring external guidance. I'm just trying to figure where I fall within that category of genius. :-(
The short answer is that I would not consider this a sign that your mental capacity is not adequate to tackle these sorts of questions.

You might be right - there are probably some students in your class who were able to solve this problem without external guidance. However, there are probably others who thought they had solved it or thought it was obvious and therefore not worth solving and they might have the wrong answer because they didn't spend any time thinking about the problem.

The process of learning requires effort on the part of the student. You made the effort to attempt the problem, ask a question to make sure you understood the problem correctly, and made another effort to solve the problem correctly and asked another question - this shows that you are engaged with the material and, at the very least, trying to understand it. THe next time you see a similar problem you might think back to this one and use what you learned as a strategy for approaching that new problem.

Some students might seem like they just magically know everything - and some of them probably do know a lot - but it's possible (and likely) that you know more than they do in another area of study.

It can be difficult when surrounded by others who are (seemingly) smarter than you but try not to compare yourself to them - instead, use them as a learning resource. It can be very helpful to have friends "smarter" than you! Good luck!
 
  • #7
failexam said:
My lecturer assigned this problem as homework and I have not been able to do it without your help. What I mean that I required external guidance. Do you think that this is a sign that my intellectual capacity is not adequate to tackle these sorts of questions?
Not necessarily. There are a lot of reasons why someone might struggle with a math course. For example, writing proofs presents a stumbling block for many students; if this is your first time writing proofs, it would not be surprising to me if you struggled. A sudden change in the type of math can also throw students off. Maybe, for whatever reason, you're just not at a point to learn the material, but a semester later, you will be. Perhaps the professor's teaching style doesn't match your learning style. A lack of intellectual capacity is a reason you should consider only after eliminating most other possibilities.

I'm sure there are students out there who could have done the problem all by themselves without requiring external guidance. I'm just trying to figure where I fall within that category of genius. :-(
It's a bit dangerous to compare yourself to others as their backgrounds can be quite different from yours. Some students will appear to get the material more easily simply because they've seen it before and they've had more time to practice.
 

FAQ: Determination of a set equality from other set equalities

1. How do you determine if two sets are equal?

The most common method to determine set equality is by comparing the elements in each set. If both sets contain the same elements, in the same quantity, then they are considered equal.

2. Can two sets with different elements still be considered equal?

No, for two sets to be considered equal, they must have the exact same elements. Even if one set has more elements than the other, they cannot be considered equal unless they have the same elements.

3. What is the difference between set equality and set equivalence?

Set equality refers to two sets having the exact same elements, while set equivalence refers to two sets having elements that can be mapped to each other in a one-to-one correspondence. In other words, two sets are equivalent if they have the same number of elements and there is a relationship between the elements of each set.

4. How does the transitive property apply to set equality?

The transitive property states that if A = B and B = C, then A = C. This means that if two sets are equal to a third set, then they are also equal to each other. This principle can be applied when determining set equality from other set equalities.

5. Are there any other methods to determine set equality besides comparison?

Yes, there are other methods such as using set operations (union, intersection, difference) or using Venn diagrams to visually represent the elements of each set. However, comparison is the most common and straightforward method for determining set equality.

Similar threads

Replies
3
Views
1K
Replies
6
Views
4K
Replies
1
Views
1K
Replies
6
Views
1K
Replies
4
Views
2K
Back
Top