Determine max force and acceleration to safely make a turn

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bornofflame
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Homework Statement


The coefficient of static friction between a tire and a dry road is about μs=0.85. What is the fastest you can safely drive the turn below?
a. Use a free-body diagram and force equations to determine the maximum force and acceleration you can achieve.
b. Use the map to estimate the radius and maximum velocity of the turn.

I don't have the map readily available but the radius is estimated at approximately 110m.

Homework Equations


F = ma
f ≤ μsN
fmax = μs-maxN
W = mg
a = V2/r

The Attempt at a Solution


a[/B].
p101-test2-redo-1.png


I drew my force diagrams and got the following (repeated from image):
y: N - mg = may = 0, so: N = mg
x: f = max = μN = μmg, so: ax = μg

amax = μg = (0.85)(9.8m/s2) = 8.33m/s2

b. r = 110m, Vmax = ?
a = V2 / r, so: V2 = ar, and V = ±√(ar),
which means:
Vmax = ±√(a⊥-maxr) = ±√(8.33m/s2⋅110m)=±30.3m/s
I'm satisfied with my answer for part b, but am including it just in case there is something that is wrong with it. My main concern, however, is part a as I can't seem to figure out how to get the Fmax which I am assuming is friction max because that is the only force at work keeping the vehicle from sliding off the road.
 

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kuruman said:
Also, I would drop the ± signs. You are calculating magnitudes of vectors here.

Ok. I'll keep that in mind. I was thinking to keep it b/c I was thinking of velocity as a vector, but it's definitely asking what is the fastest. Thanks for pointing that out.

TSny said:
If you aren't given the mass of the vehicle, then I don't think you can get a numerical value for the force.

Yeah. Unfortunately no mass which is what's blocking me.
 
haruspex said:
I'm not sure it wants a numerical value for that. The way it is worded, it could just be telling you the steps to go through to find the speed.

Okay. I wasn't sure that there was a way to replace mass that I just wasn't seeing. I'll follow up with my professor. Thanks.