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An unknown solution is 40 times more alkaline than neutral water which has a PH of 7. Determine the PH of the unknown solution.

Here is what I have:

40 = (log base 10 x)/(log base 10 7)

40 = 10^(x-7)

10^1.4 = 10^(x-7)

1.4 = x - 7

x = 8.4

The answer is supposed to be 8.6??? Not sure where my mistake is.

Thanks for your help.

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# Homework Help: Determine PH of this solution

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