Determine the magnitude and direction of the effective value of g

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SUMMARY

The effective value of gravitational acceleration (g) at a latitude of 45 degrees on Earth is influenced by both gravitational and centrifugal forces due to Earth's rotation. The gravitational force acts towards the center of the Earth, while the centrifugal force acts outward, reducing the net weight of objects. A vector diagram is essential to illustrate these forces, with the net acceleration determining the effective weight. This analysis requires understanding of circular motion and the concept of non-inertial frames of reference.

PREREQUISITES
  • Understanding of gravitational force and its components
  • Knowledge of centripetal force and circular motion
  • Familiarity with vector diagrams in physics
  • Concept of non-inertial frames of reference
NEXT STEPS
  • Study vector diagrams for forces in circular motion
  • Learn about gravitational force components at different latitudes
  • Explore the effects of Earth's rotation on gravitational acceleration
  • Investigate non-inertial reference frames and pseudo forces
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and gravitational forces, as well as educators looking to explain the effects of Earth's rotation on weight and acceleration.

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Homework Statement


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Determine the magnitude and direction of the effective value of g at a latitude of 45 degrees on the Earth. Assume the Earth is a rotating sphere.

Homework Equations



a = v2/r

The Attempt at a Solution



This question requires a vector diagram no doubt.
What I know is that there is gravity force towards to center of the Earth and normal force exactly opposite to it, and also centripetal force along the x axis. But centripetal force here confuses me as I don't know how to draw it. In my early problems with circular uniform motion, centripetal force was always component of some other force -like normal force, tension force, or friction force. I don't recall drawing an Fcentripetal in the vector diagram for questions like these:

fetch.php?media=phy141%3Alectures%3Aconicalpendulum.png
carbank.gif



But in this gravity question, I think I need to show that there is an Fcentripetal along the x axis? Or is it nothing more than a component of gravity force?
 
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An object on the surface of the Earth moves in a circle about the axis of rotation of the Earth, so there must be something providing the centripetal force. You're right that it is a portion of the gravitational force that is co-opted for this purpose. The net weight of objects are decreased accordingly, and the net direction for the weight vector is deflected a small amount away from "straight down" to the center of the Earth when the object in question is not located on the equator.

If you choose as your frame of reference the rotating Earth (a non-inertial frame of reference since it's rotating) it allows you to speak of a centrifugal pseudo force without getting too many vocal objections from physicists :) In that case you can draw a free-body diagram for an object and pencil in the gravitational acceleration and centrifugal acceleration. Sum them to find the net acceleration. That net acceleration is what produces the effective weight of the object.
 
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