The quarter ring has mass m and was cut from a thin uniform plate. Knowing that r1 = 1/2r2 determine the mass moment of inertia of the quarter ring with respect to A. axis AA' B. The centroidal axis CC' that is perpendicular to the plane of the quarter ring.
CC' is located possibly where the center of mass is? (See attached file). EDIT: obviously it is the centroid.. the problem says centroidal axis, I'm dumb..
IAA' = 1/4mr2
ICC' = 1/2mr2
Parallel Axis Theorem
I = I(bar) + md2
The Attempt at a Solution
I originally tried to just use the mass moments of inertia to calculate it. I then realized that the center of mass of the quarter annulus will not be at the origin O in this case so I probably will have to use the parallel axis theorem.
I am really lost on this and I originally calculated
IAA' = (1/16)m(r22 - (1/2)r22)
ICC' = (1/8)m(r22 - (1/2)r22)
73.1 KB Views: 751