- #1

- 68

- 0

* ---------- *

One point particle denoted Q1 = -2.50e-3 C and Q2 = 6.00 e-3 C

the distance of separation is 1.00 m..

I am not sure how to determine R, s.t. my Electric field is Zero.

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter georgeh
- Start date

- #1

- 68

- 0

* ---------- *

One point particle denoted Q1 = -2.50e-3 C and Q2 = 6.00 e-3 C

the distance of separation is 1.00 m..

I am not sure how to determine R, s.t. my Electric field is Zero.

- #2

- 809

- 0

georgeh said:

* ---------- *

One point particle denoted Q1 = -2.50e-3 C and Q2 = 6.00 e-3 C

the distance of separation is 1.00 m..

I am not sure how to determine R, s.t. my Electric field is Zero.

Do you know what R is?

- #3

- 68

- 0

- #4

- 809

- 0

For example if you had this configuration below

(-q)---------------(q)

|<----- 1m -------->|

Then if you wanted the distance from (-q) called R, you would have:

R<------- (-q)---------------(q)

Now the distance from (q) would be R+1m

do you see why it's important?

- #5

- 4

- 0

- #6

Born2bwire

Science Advisor

Gold Member

- 1,779

- 22

Now with this problem, the two charges are fixed in relation to eachother. So the first thing is to setup up an equation for the total field using a single vector to represent the distance instead of two. FrogPad shows one such way to do this. Now, you could have a situation where you can't have any nulls, but I think we can assume that it will not be the case. Don't forget that the electric field is a vector, not just a scalar.

- #7

- 4

- 0

k2.5x10^-6/X^2 = k6x10^-6/(X+1)^2

but not getting the answer the book gives :( seriously these electrical charges and things just aint making sense to me!

Share:

- Replies
- 8

- Views
- 18K