Determine the specific latent heat of vaporization of water

Click For Summary
SUMMARY

The discussion centers on calculating the specific latent heat of vaporization of water using experimental data. The initial mass of water is 400g, and the final mass is 450g, indicating 50g of steam condensed. The specific heat capacities of water and the calorimeter are 4200 J/kg°C and 420 J/kg°C, respectively. The equation used is Q = m hfg, leading to a calculated value of 562.075 x 10^-9 J/kg for the latent heat, which requires verification and further analysis.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically latent heat.
  • Familiarity with specific heat capacity calculations.
  • Knowledge of mass-energy balance in calorimetry.
  • Proficiency in algebraic manipulation of equations.
NEXT STEPS
  • Review the derivation of the latent heat of vaporization formula.
  • Learn about calorimetry and its applications in thermal energy calculations.
  • Explore the concept of phase changes and their energy requirements.
  • Investigate the specific heat capacities of various substances for comparative analysis.
USEFUL FOR

Students in physics or engineering courses, particularly those focusing on thermodynamics and calorimetry, will benefit from this discussion. It is also relevant for anyone conducting experiments related to heat transfer and phase changes.

series111
Messages
54
Reaction score
0

Homework Statement


from the following observations made during an experiment,determine the specific latent heat of vaporisation of water.

initial mass of water 400g
final mass of water 450g
mass of calorimeter 200g
initial temperature of water & calorimeter 16 degrees
final temperature of water & calorimeter 70 degrees
specific heat capacity of water 4200 j/kg degrees
specific heat capacity of calorimeter 420 j/kg degrees


Homework Equations



Q= m hfg

The Attempt at a Solution



let suffix s = steam w = water and c = calorimeter

-ms hfg = mw cw delta tw + mc cc delta tc + ms cw delta ts

-50 = 400x4200x(70-16)+200x420x(70-16)+50x4200x(70-100)=88.956x10 6

therefore 50/88.956x10 6 = 562.075 x 10 -9

if someone would be so kind to check if this is right it will be much appreciated.
 
Physics news on Phys.org
i forgot to state the final mass of water is 450g the extra 50 is condensed steam please can someone tell me if this is right or some pointers if i have it wrong because this question is relevant to my coursework i don't want the answer just help.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
638
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K