from the following observations made during an experiment,determine the specific latent heat of vaporisation of water.
initial mass of water 400g
final mass of water 450g
mass of calorimeter 200g
initial temperature of water & calorimeter 16 degrees
final temperature of water & calorimeter 70 degrees
specific heat capacity of water 4200 j/kg degrees
specific heat capacity of calorimeter 420 j/kg degrees
Q= m hfg
The Attempt at a Solution
let suffix s = steam w = water and c = calorimeter
-ms hfg = mw cw delta tw + mc cc delta tc + ms cw delta ts
-50 = 400x4200x(70-16)+200x420x(70-16)+50x4200x(70-100)=88.956x10 6
therefore 50/88.956x10 6 = 562.075 x 10 -9
if someone would be so kind to check if this is right it will be much appreciated.