Determine the wave function of the particle

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Homework Help Overview

The discussion revolves around determining the wave function of a particle interacting with a potential barrier defined in three regions. The problem involves analyzing the wave function in different potential regions and understanding the relationship between the amplitudes of incident and reflected waves.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to express the wave function in different regions and apply boundary conditions to find relationships between the amplitudes of the incident and reflected waves.
  • Some participants question the interpretation of the amplitude ratio B/A and its implications for the reflected wave.
  • Others suggest rewriting the wave function using complex exponentials to simplify the expressions and facilitate further analysis.
  • There is a discussion about simplifying complex expressions and identifying common factors in the equations derived from boundary conditions.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations and approaches to the problem. Some guidance has been offered regarding the mathematical manipulation of the wave functions and the significance of the amplitude ratio, but no consensus has been reached on the specific simplifications or interpretations.

Contextual Notes

Participants express uncertainty about the meaning of the amplitude ratio B/A and its physical significance in the context of the problem. There is also mention of the complexity of the expressions derived from the boundary conditions, indicating potential challenges in simplifying them.

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Homework Statement



A particle coming from +∞ with energy E colides with a potential of the form:

V = ∞ , x<0 (III)
V = -V0 , 0<x<a (II)
V = 0, x>a (I)

a) Determine the wave function of the particle considering that the amplitude of the incident wave is A. Writting the amplitude of the reflected wave at x=a in the form

\frac{B}{A} = e^{i\delta}

determine \delta . What is the value of \delta in the limit where V0 = 0 ?

b) Determine the probability density current in x>a

The Attempt at a Solution



a)

For region I :

\Psi_{I} (x) = Ae^{-ikx} + Be^{ikx} , k=\frac{\sqrt{2mE}}{\hbar}

II:

\Psi_{II} (x) = Csin(lx) + Dcos(lx) , l=\frac{\sqrt{2(mE+V_{0}}}{\hbar}

III:

\Psi_{III} (x) = 0Boundary conditions:

at x=0:

0 = Csin(lx) + Dcos(lx) (=) D = 0

So \Psi_{II} (x) = Csin(lx)

at x=a:

Ae^{-ika} + Be^{ika} = Csin(la) (1)

and

-ikAe^{-ika} + ikBe^{ika} = lCcos(la) (2)

Dividing (1) for (2) I got:

\frac{B}{A} = e^{-2ika} \frac{(-\frac{1}{l}tan(la)ik-1)}{(1-\frac{1}{l}tan(la)ik)}

How can I get rid of that constant that is multiplying by the exponential? Is this even right?
 
Last edited:
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B/A appears to be a complex number - is that right?

Note: did you try writing ##\psi_{II}## as a sum of complex exponentials?
 
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Simon Bridge said:
B/A appears to be a complex number - is that right?

Note: did you try writing ##\psi_{II}## as a sum of complex exponentials?


Hi Simon Bridge, thank you for your reply.

I did write psiII as a sum of complex exponentials and I got the following:

\frac{B}{A} = \frac{\frac{k}{l}e^(ika-ila)-\frac{k}{l}e^(-ika + ila) - e^(-ika -ila) - e^(-ika + ila)}{\frac{k}{l}e^(ika-ila) - \frac{k}{l}e^(ika+ila) +e^(ika+ila) + e^(ika-ila)}

is there any way to simplify this ? This problem is killing me, because I'm not even sure what "writing the amplitude of the reflected wave at x=a in the form \frac{B}{A} " means.

I mean, I assumed the amplitude of the reflected wave at x=a is B, if I write B/A it isn't the amplitude of the reflected wave anymore.
 
B/A is the proportion of the incident amplitude that is reflected.
If you multiplied it by 100, you's be able to say, "100B/A percent got reflected".

You basically have to look for common factors and cancel things off a bit at a time.
It is not going to be easy. But that, I am afraid, is the exercise.

Note: ##e^{a-b}+e^{-a-b}=(e^a+e^{-a})e^{-b}## ... stuff like that. maybe ##e^{-b}## cancels something in the denominator? If not - look for something else.

Of course, since they are all constant terms, it may be possible to add them up geometrically.
Separate the real and imaginary components.
 
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