Determine units of variables in formula

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Homework Help Overview

The problem involves determining the units of variables in the equation v = at² + bt³, where v represents velocity in meters per second (m/s) and t represents time in seconds. Participants are exploring how to mathematically derive the units for constants a and b based on the equation's structure.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need for the units on both sides of the equation to match, with some attempting to plug in units directly to see if they work out. Others express confusion about how the powers of time (t² and t³) affect the units and question the reasoning behind the units assigned to a and b.

Discussion Status

There is an ongoing exploration of different unit options for a and b, with participants testing various choices and expressing uncertainty about the results. Some have suggested that the units for a could be m/s³ and for b could be m/s⁴, but there is no consensus on the correct options due to the multiple-choice nature of the problem.

Contextual Notes

Participants note that the problem is part of a multiple-choice test, which adds complexity to their reasoning as they seek to match their derived units with the provided options. There is also mention of a desire for clarity on the original question and answer choices.

1MileCrash
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Homework Statement



During a short interval of time, the velocity v in m/s of an automobile is given by v=at^2 + bt^3 where the time is t in seconds. The units of a and b are...

Homework Equations





The Attempt at a Solution



Alright, here's the thing. A friend gave me some old physics tests, I'm taking it in the fall and familiarizing. I don't know how to do it mathematically. I tried just "plugging in" the units to see if it works out (it's multiple choice here) but I want a way to do it mathematically.

Someone, just give me a nudge in the right direction so I can attempt here if you'd be so kind. I don't want the answer, or even too big of a hint.
 
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Hint: The units on both sides of the equation must match after all mathematical operations are completed.
 
v(m/s)= a(?) t^2(m^2/s^2)+ b(?)t^3(m^3/t^3)
The "(?)" are the unknown units. As SteamKing said the units on both sides of the equation must be the same.
 
Thanks.

How does t^2 and t^3 affect the units?

For example, (1 m/s)t^2 does what to m/s? Adds exponends to s, making m/s^3? Or add exponents to both, making m^3/s^3, or neither?
 
Could someone give me more info? I worked out all of the choices and I never get the same units. HallsofIvy, what are you doing when you say v(m/s)= a(?) t^2(m^2/s^2)+ b(?)t^3(m^3/t^3) ? Why are those units after t^2 and t^3? Where did they come from?

v = at^2 + bt^3

Option one, m/s^2 and m/s^3 respectively.

v = (m/s^2)(s^2) + (m/s^3)(s^3)

v = (ms^2/s^2 ) + (ms^3/s^3)

v = m + m

No.

Option Two, m/s^4 and m/s^5 respectively.

v = (m/s^4)(s^2) + (m/s^5)(s^3)
v = (ms^2/s^4) + (ms^3/s^5)
v = m/s^2 + m/s^2

No.

Option Three, s^3/m and s^4/m, respectively.

v = (s^3/m)(s^2) + (s^4/m)(s^3)
v = s^5/m + s^7/m

Hell no.

Option Four, m*s^2 and m*s^4, respectively.

v = (m*s^2)(s^2) + (m*s^4)(s^4)
v = ms^2s^4 + ms^3s^7

Bigger Hell no.

I am completely and utterly lost.
 
Last edited:
1MileCrash said:
Could someone give me more info? I worked out all of the choices and I never get the same units.
But there are infinitely many choices! Random guessing is no way to solve the problem.

v = at^2 + bt^3

v units are m/s. So units of a*t^2 must be m/s as well. And we know t has units of s:

a*s^2 = m/s​

Solve for a.
 
It's a multiple choice problem..

at^2 and I want m/s, my logic says that:

m/s = a(s^2)

(1/s^2)(m/s) = a
m/s^3 = a

Yet this is not an option as the a unit.
 
1MileCrash said:
It's a multiple choice problem..
Ah, okay.
at^2 and I want m/s, my logic says that:

m/s = a(s^2)

(1/s^2)(m/s) = a
m/s^3 = a

Yet this is not an option as the a unit.
Then the choices are all wrong, since m/s3 are the correct units for a.
 
1MileCrash said:
It's a multiple choice problem..

at^2 and I want m/s, my logic says that:

m/s = a(s^2)

(1/s^2)(m/s) = a
m/s^3 = a

Yet this is not an option as the a unit.
Let's assume for a moment that m/s3 is an option. You have m/s3 * s2 = m/s, the correct units for velocity. Why do you think your answer is not an option?
 
  • #10
Again, because it is a multiple choice problem. I'm not saying that the unit is physically impossible, meaningless, or anything else like that. It's just not an option on the test paper out of a, b, c, and d.

That's why I tested the four "options" above.
 
  • #11
1MileCrash said:
Again, because it is a multiple choice problem. I'm not saying that the unit is physically impossible, meaningless, or anything else like that. It's just not an option on the test paper out of a, b, c, and d.

That's why I tested the four "options" above.

As a sceptical reader, I would ask that you try to provide a copy of the original question and optional answers.
Not a transcription, but a scan.
 
  • #12
1MileCrash said:

Homework Statement



During a short interval of time, the velocity v in m/s of an automobile is given by v=at^2 + bt^3 where the time is t in seconds. The units of a and b are...

Homework Equations





The Attempt at a Solution



Alright, here's the thing. A friend gave me some old physics tests, I'm taking it in the fall and familiarizing. I don't know how to do it mathematically. I tried just "plugging in" the units to see if it works out (it's multiple choice here) but I want a way to do it mathematically.

Someone, just give me a nudge in the right direction so I can attempt here if you'd be so kind. I don't want the answer, or even too big of a hint.

First, let's just look at a

v = at2

dimensionally [in units] that is

[m/s] = [a] x [s2]

"divide" both sides my s2 we get [a] = [m/s3]

doing a similar operation for b means that dimensionally

= [m/s4]
 

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