Determine whether A is orbiting B

  • Thread starter Thread starter h4tt3n
  • Start date Start date
AI Thread Summary
To determine if one object is in a closed elliptical orbit around another, calculate the total mechanical energy of the two-body system using their mass, position, and velocity vectors. If the total energy is less than zero (E < 0), the system is bound, indicating that the objects are in elliptical orbits around their center of mass. It may be beneficial to analyze the problem from the center of mass reference frame, applying the concept of reduced mass to simplify calculations. In this frame, the total energy can be expressed in terms of the reduced mass and the total mass of the system. Properly using the center of mass frame is crucial for accurate energy assessments.
h4tt3n
Messages
10
Reaction score
0
Hello,

I'm looking for a way to determine wether one object is in a closed elliptical orbit around another based on their mass and state vectors. For instance, if looking at the state vectors of the distant irreguar Jupiter-moon Sinope and of an asteroid passing by Jupiter at the roughly same distance and velocity, it wouldn't be obvious that one was just barely orbiting the planet and the other one wasn't. How do I calculate this from their mass, position and velocity vectors?

Cheers,
Mike
 
Astronomy news on Phys.org
You can calculate the total mechanical energy (kinetic + potential) of the two-body system:
$$ E = \frac{1}{2}m_1|\vec{v_1}|^2 + \frac{1}{2}m_2|\vec{v_2}|^2 - G\frac{m_1m_2}{|\vec{r_2} - \vec{r_1}|} $$ If ##E < 0## then the system is bound, and the two bodies orbits about the center of mass in elliptical trajectories.

Note: sometimes it might be more convenient to solve the problem from the reference frame of the center of mass. In such case the concept of reduced mass can be applied and the two body-problem reduces to one-body problem (total mass of the system ##M## is fixed at the origin and the reduced mass ##\mu## is orbiting around). In such case, the total energy can be calculated as:
$$ E = \frac{1}{2} \mu|\vec{v}|^2 - G\frac{M \mu}{|\vec{r}|} $$
 
And note you actually have to use the center of mass frame, or else the total mechanical energy won't mean much.
 
TL;DR Summary: In 3 years, the Square Kilometre Array (SKA) telescope (or rather, a system of telescopes) should be put into operation. In case of failure to detect alien signals, it will further expand the radius of the so-called silence (or rather, radio silence) of the Universe. Is there any sense in this or is blissful ignorance better? In 3 years, the Square Kilometre Array (SKA) telescope (or rather, a system of telescopes) should be put into operation. In case of failure to detect...
Thread 'Could gamma-ray bursts have an intragalactic origin?'
This is indirectly evidenced by a map of the distribution of gamma-ray bursts in the night sky, made in the form of an elongated globe. And also the weakening of gamma radiation by the disk and the center of the Milky Way, which leads to anisotropy in the possibilities of observing gamma-ray bursts. My line of reasoning is as follows: 1. Gamma radiation should be absorbed to some extent by dust and other components of the interstellar medium. As a result, with an extragalactic origin, fewer...
This thread is dedicated to the beauty and awesomeness of our Universe. If you feel like it, please share video clips and photos (or nice animations) of space and objects in space in this thread. Your posts, clips and photos may by all means include scientific information; that does not make it less beautiful to me (n.b. the posts must of course comply with the PF guidelines, i.e. regarding science, only mainstream science is allowed, fringe/pseudoscience is not allowed). n.b. I start this...
Back
Top