Determine which triangle is this

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The discussion revolves around determining the type of triangle ΔABC based on the condition involving its ex-radii, expressed as (1 - r1/r2)(1 - r1/r3) = 2. Participants derive equations such as a² + 2b² + 2c² + 3bc = 3ac + 3ab and a sum involving the tangents of half-angles, but find it challenging to identify the triangle type solely from these equations. Clarification is provided that r1, r2, and r3 refer to the ex-radii of the triangle. The conversation also references helpful formulas from Wolfram MathWorld to assist in further analysis. Overall, the thread highlights the complexity of the problem and the need for additional insights to classify the triangle accurately.
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Homework Statement


If in a ΔABC , \left( 1-\dfrac{r_1}{r_2} \right) \left( 1-\dfrac{r_1}{r_3} \right) = 2
then which triangle is it?

r1, r2, r3 denotes ex-radii.

The Attempt at a Solution



I get this condition

a^2+2b^2+2c^2+3bc=3ac+3ab

Also

\sum tan \frac{A}{2} tan \frac{B}{2} = tan^2 \frac{A}{2}

where sigma denotes the sum of products of tan of the half-angles taken pairwise.

But it is difficult to figure out the type of triangle by just looking at the above two eqns.
 
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utkarshakash said:

Homework Statement


If in a ΔABC , \left( 1-\dfrac{r_1}{r_2} \right) \left( 1-\dfrac{r_1}{r_3} \right) = 2
then which triangle is it?

The Attempt at a Solution



I get this condition

a^2+2b^2+2c^2+3bc=3ac+3ab

Also

\sum tan \frac{A}{2} tan \frac{B}{2} = tan^2 \frac{A}{2}

where sigma denotes the sum of products of tan of the half-angles taken pairwise.

But it is difficult to figure out the type of triangle by just looking at the above two eqns.

What do ##r_1, r_2, r_3## mean? Are they angles, sides, or what?
 
Ray Vickson said:
What do ##r_1, r_2, r_3## mean? Are they angles, sides, or what?

They are the ex-radii.
 
Pranav-Arora said:
Rewrite the given equation as

$$r_1r_2+r_2r_3+r_1r_3=r_1^2$$

The formulas mentioned in the following link are helpful to proceed further.

http://mathworld.wolfram.com/Exradius.html

Thanks. The formulas given in Wolfram were of great help.
 
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