High School Determining ansatz for forced oscillations in SHM

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SUMMARY

The discussion focuses on the use of an ansatz for solving forced oscillations in simple harmonic motion (SHM), specifically referencing the Feynman Lectures on Physics. The proposed solution for a damped oscillator is given by $$x = \hat{x}e^{iwt}$$, derived from the differential equation $$m \ddot{x} + c \dot{x} + kx = F_0 \cos{wt}$$. Participants explore the rationale behind this ansatz, emphasizing its suitability for scenarios involving forced oscillations and the underlying mathematical principles that validate its use.

PREREQUISITES
  • Understanding of second-order differential equations
  • Familiarity with the concepts of forced oscillations and damping
  • Knowledge of complex exponentials and their relation to trigonometric functions
  • Experience with linear ordinary differential equations (ODEs)
NEXT STEPS
  • Study the derivation of solutions for damped oscillators in classical mechanics
  • Learn about the method of undetermined coefficients in differential equations
  • Explore the application of Fourier series in solving differential equations
  • Investigate the role of complex numbers in oscillatory motion analysis
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Students and professionals in physics, particularly those studying mechanics and oscillatory systems, as well as mathematicians interested in differential equations and their applications in real-world scenarios.

etotheipi
I've generally solved introductory second order differential equations the 'normal' way; that is, using the auxiliary equation, and if it is inhomogeneous looking at the complementary function as well, and so on.

I know that sometimes it can be helpful to propose an ansatz and substitute it into determine unknown coefficients. In this section of the Feynman lectures (http://www.feynmanlectures.caltech.edu/I_23.html) he proposes a solution to a damped oscillator with forced oscillations of the real part of $$x = \hat{x}e^{iwt}$$where the original differential equation was$$m \ddot{x} + c \dot{x} + kx = F_0 \cos{wt}$$How has he determined that this is a suitable ansatz for the scenario? Is this particular ansatz only applicable when forced oscillations are involved (excluding the obvious simplest case with no damping or periodic force)?N.B. I am not concerned about the complex exponential, the real part of which is \cos{\omega t}, but more why this expression has been deemed suitable for the case with forced oscillations (though of course it does actually work, and we could also obtain a solution of that form from first principles of differential equations).

Thank you!
 
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etotheipi said:
I've generally solved introductory second order differential equations the 'normal' way; that is, using the auxiliary equation, and if it is inhomogeneous looking at the complementary function as well, and so on.

I know that sometimes it can be helpful to propose an ansatz and substitute it into determine unknown coefficients. In this section of the Feynman lectures (http://www.feynmanlectures.caltech.edu/I_23.html) he proposes a solution to a damped oscillator with forced oscillations of the real part of $$x = \hat{x}e^{iwt}$$where the original differential equation was$$m \ddot{x} + c \dot{x} + kx = F_0 \cos{wt}$$How has he determined that this is a suitable ansatz for the scenario? Is this particular ansatz only applicable when forced oscillations are involved (excluding the obvious simplest case with no damping or periodic force)?N.B. I am not concerned about the complex exponential, the real part of which is \cos{\omega t}, but more why this expression has been deemed suitable for the case with forced oscillations (though of course it does actually work, and we could also obtain a solution of that form from first principles of differential equations).

Thank you!
Not entirely sure I understand your question, but I believe mathematicians looked at the linear ODE structure and thought what function, if differentiated, can be summed to be itself? The answer is, of course, a series solution taking the form ##\sum_i a_i x^i## where the coefficients ##a## are to be determined. This makes sense, right? Consider the homogenous solution to the undamped system ##\ddot x + k/m x = 0##. Guessing $$y = \sum_ia_i x^i = a_0 + a_1x + a_2x^2+a_3x^3+... \implies\\
y''=2a_2+6a_3x+... \implies\\
\ddot x + \frac k m x = 0 \implies\\
2a_2+6a_3x+... + \frac k m (a_0 + a_1x + a_2x^2+a_3x^3+...) \implies\\
(2a_2+\frac k m a_0) + (6a_3 + a_1)x + ... = 0 + 0x \implies\\
2a_2+\frac k m a_0 = 0,\,\,\, 6a_3 + a_1 = 0$$

(sorry, my ##x##'s should be ##t##'s and my ##y##'s should be ##x##'s, but you get the idea.
 
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