- #1

- 18

- 0

Hi, sorry to disturb you,

But with the equation f(x)= x^2+2x/(x-2)^2

I need to find the intervals at which f(x) is concave up, and down.

I found f '(x)= (2x+2)(x-2)^2 -2(x-2)(x^2+x)/((x-2)^4)

From there I equated it to 0, and found the critical points to be x=2,-2/3.

However, I have just noticed there is a point of inflection at x=-2. How did I miss this point in my calculation for critical points, any help would be much obliged.

Thanks

But with the equation f(x)= x^2+2x/(x-2)^2

I need to find the intervals at which f(x) is concave up, and down.

I found f '(x)= (2x+2)(x-2)^2 -2(x-2)(x^2+x)/((x-2)^4)

From there I equated it to 0, and found the critical points to be x=2,-2/3.

However, I have just noticed there is a point of inflection at x=-2. How did I miss this point in my calculation for critical points, any help would be much obliged.

Thanks

Last edited: