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I want to know what current i am getting out of a supercapacitor, but i have nothing to directly measure the currents in the given range with.

So i tried to determine it from the voltage drop on the cap, and i want to know if i did it right.

Given is 3000F capacitor, at initial voltage of V1=1.100V.

After being connected to the load in question for 3.5 seconds, the voltage is V2=1.045V.

Thus, the energy in the capacitor is 0.5*C*V*V.

E1=1815J

E2=1638J

Which gives spent energy of 177J.

W=J/s, so for the 3.5 seconds it was giving out 50.5W of power.

Finally, A=W/V, and average V was 1.0725V, which gives 47.1A of current.

Is that a correct way of current estimation?

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# Determining current drawn from a capacitor

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