Determining if polynomial function

AI Thread Summary
A polynomial function must have only positive integer exponents for its variables, and coefficients can be any real numbers, not just rational ones. Expressions like 3x^-1 - 11 and y = sqrt(3x^2 - 5x) are not polynomials due to the presence of negative and fractional exponents. The expression 1 / (x^3 - 4) can also be problematic, as it can imply a negative exponent depending on its interpretation. Understanding the properties of exponents is crucial for determining whether a function is polynomial. Overall, clarity in notation and exponent rules is essential for correctly identifying polynomial functions.
Nelo
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Homework Statement



We know that a polynomial function is anything with a positive exponent and a rational number.

a) - / x^3 -4


d) 3x^-1 - 11

g) y= [sqrt of term]3x^2 -5x


Homework Equations





The Attempt at a Solution



c) 1 / x^3 - 4
(do we use exponents to verify ?)
i
e) 1^1 / x^3 -4^1
1-3 = -2 , 1-1 = 0
Therefore there is a negetive exponent on the x^3, is that why?

4d) y= 3^x-1 - 11
(how do u know this isnt?)

g) [sqrtofentireterm] 3x^3-5x

Why is that not a polynomial function?

Thnx 4 the help!
 
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Nelo said:

Homework Statement



We know that a polynomial function is anything with a positive exponent and a rational number.
No, we don't know that! That is wrong. A polynomial function can has the variable, x, only to positive integer exponents. The coefficients can be any numbers, not just rational numbers.

a) - / x^3 -4
what does the "-/" mean? Is that an attempt at a squareroot symbol? Better would be "sqrt(x^3- 4) which is the same as (x^3- 4)^(1/2). That's not a polynomial because it has a fractional exponent.

d) 3x^-1 - 11
negative exponent

g) y= [sqrt of term]3x^2 -5x
again, sqrt= exponent 1/2.

Homework Equations





The Attempt at a Solution



c) 1 / x^3 - 4
(do we use exponents to verify ?)
is that 1/(x^3- 4) or (1/x^3)- 4?
In either case, there is a negative exponent, (x^3- 4)^(-1) or x^(-3)- 4.

e) 1^1 / x^3 -4^1
1-3 = -2 , 1-1 = 0
I hav no clue what you are doing here.

Therefore there is a negetive exponent on the x^3, is that why?

4d) y= 3^x-1 - 11
(how do u know this isnt?)
3^(x- 1) does not have x to a power.

g) [sqrtofentireterm] 3x^3-5x

Why is that not a polynomial function?
Again, because of the square root= 1/2 power.

Thnx 4 the help!
 
Therefore there is a negetive exponent on the x^3, is that why?

4d) y= 3^x-1 - 11
(how do u know this isnt?)

3^(x- 1) does not have x to a power

Why do you mean does not have x to a power??


c) 1 / x^3 - 4
(do we use exponents to verify ?)

is that 1/(x^3- 4) or (1/x^3)- 4?
In either case, there is a negative exponent, (x^3- 4)^(-1) or x^(-3)- 4.

How is there a negetive exponent there... how do u verify? There is no braackets anywhere on my page so i wrote it as written. Do u evalue the exponents in the divsion and then it comes out as a negetive exponent?
 
Nelo said:
How is there a negetive exponent there... how do u verify? There is no braackets anywhere on my page so i wrote it as written. Do u evalue the exponents in the divsion and then it comes out as a negetive exponent?
Do you know the properties of exponents? Specifically, this one:
a^{-n} = \frac{1}{a^n}, a \ne 0
If not, you'll need to review them.
 
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