Determining Sample Size for Conversion to Ag2S

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To determine the sample size for conversion to Ag2S, the sulfur content of the mineral must be expressed in relation to the desired mass of Ag2S. If the sample contains x% sulfur, the mass of sulfur in the sample can be calculated as m * (x/100). The goal is to find a mass m such that the grams of Ag2S produced equals four times the percent sulfur in the sample. This leads to the equation m * (x/100) * (molar mass of Ag2S) = 4 * (x/100). Ultimately, solving for m will provide the necessary sample size for the conversion.
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Sometimes, when repeated assays are to be performed, the sample size is standardized and chosen such that the ultimately measured quantigy is numerically equivalent to some other desired proportionate quantity.

suppose the sulfur content of a mineral sample is determined by complete conversion to Ag2S(s) what mass of sample must be chosen so that the number of grams of Ag2S obtained is equal to 4 times the percent sulfur in the sample??


i don't know where do start...
 
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Begin here: Let the sample contain x% of sulfur (S) and have a mass m. Then the mass of S in the sample is ...
 
how do i find mass if i don't know how much Ag2S i have?
 
Assume the mass is "m" and write down an expression for the mass of S in terms of x and m.
 
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