Determining the direction of electric field flow and the sign on potential difference

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SUMMARY

The discussion focuses on determining the direction of the electric field and the sign of the potential difference in a radial resistor with inner radius r1 and outer radius r2, characterized by conductivity sigma. The electric field points radially outward, aligning with the direction of current flow, which indicates a flow of positive charge. Consequently, the potential difference V2 - V1 is positive, as the potential drop occurs in the direction of current flow, consistent with Ohm's Law (E = IR).

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Homework Statement



A resistor made from a shell with an inner radius r1 and an outer radius r2 hasa conductivity sigma. The current flows radially outward.
1.What direction does the E field point in.
2. Is the potential difference V2-V1 positive or negative.

Homework Equations


None, problem is conceptual.


The Attempt at a Solution


As far as I know the electric field flows towards an negative charge and away from a positive charge. I believe that the direction a current flow indicates a flow of positive charge. Thus if a positive charge is flowing outward then the electric field must also be flowing outward in order to move away from the positive charge.

The potential difference here I believe would also be positive. This is just because in problems that I've done before when it was positive the electric current was flowing outward. This however, may just be cowincedence. Can someone please explain this concept to me.

Thank you for your time.
 
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Yes, it's basically Ohm's Law. When current flows through a resistance there is a potential drop in the direction of the current flow: E = IR.
 

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