Determining the infinite limit

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Can someone help me determine the infinite limit :

lim
x->0


x-1
x^4(x+2)

Much appreciated
 
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parisian said:
Can someone help me determine the infinite limit :

lim
x->0


x-1
x^4(x+2)

Much appreciated

Trying to line up numerator and denominator is a very bad idea on the internet: use parentheses: (x-1)/(x^4(x+2)) or, better, use "LaTex":
\lim_{x\rightarrow 0}\frac{x-1}{x^4(x+2)}

However, now I have a problem with "determine the infinite limit". Why do you want help determining it? You just said it was "infinite"! The limit goes to infinity which is to say that the limit does not exist. You can separate it as (1/x^4)((x-1)/(x+2)). As x goes to 0, the right hand fraction goes to a finite limit, -1/2. Since (1/x^4) obviously goes to infinity, so does the entire fraction.
 
True

:P

Thanks any ways
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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