[tex]T = \sqrt { \frac{2d} {g} }[/tex](adsbygoogle = window.adsbygoogle || []).push({});

Therefore (and I had to come up with this on my own because I could not find it on the internet :rofl:)

[tex]D = \frac{t^2 * g} {2}[/tex]

But I cannot find the logic in why the time equals 2 times the distance over the acceleration of gravity on earth. Now, I do understand the units. The Time is in seconds, and the Distance is in meters, because the acceleration is in meters per second (any other units will work just fine).

But why is the distance multiplied by 2?

And why is the square root function used?

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# Deviation of Newton's Gravity Equations

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