Diagonalization of square matrix if not all eigenvalues are distinct of

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Uncle_John
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Is it possible to diagonalize such matrix? and how would one do it?
 
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Yes, it is possible to diagonalize such a matrix. One has to find the eigenspaces and a basis for the eigenspaces. Take all the basisvectors for the eigenspaces, if they span the entire space, then the matrix is diagonalizable.
Taking all the basis eigenvectors as a basis gives you the required diagonal matrix.