Difference Between Partial and Ordinary Differentials

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Differentials in calculus represent quantities, with the relationship dx/dx=1 illustrating this concept. The chain rule demonstrates how differentials can be manipulated, as seen in dy/dx=(dy/du)(du/dx). In contrast, partial derivatives, introduced in multivariable calculus, are denoted as ∂f/∂x and ∂f/∂y, emphasizing their role in functions of multiple variables. Unlike ordinary derivatives, partial derivatives do not guarantee differentiability or continuity of a function at a point, as shown by the example of f(x,y)=0 if xy=0, which has zero partial derivatives at (0,0) but is not continuous there. Understanding these distinctions is crucial for grasping the behavior of functions in different contexts.
Pinu7
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I have been wanting to ask this for a while.

In Calc I, I was introduced to differentials. It seemed like they act like quantities(please corrected me if I'm wrong). For example dx/dx=1. You can obtain this by differentiating x or by eliminating the dx in the numerator and denominator(I do not know why this worked).

What convinced me that differentials where quantities was the chain rule. dy/dx=(dy/du)(du/dx). The proof is a bit tough, but you will obtain the same result by eliminating the du.(I may be making a TREMENDOUS mathematical blunder here, but it seemes to work)

In Calc III, I was introduced to \partialx and\partialy. Obviously I found out that \partialx\neqdx or else the chain rule for multiple variables would not simplify to dz/du.

So, why are these two infinitesimals so different?
 
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No, you were not "introduced to \partial x and \partial y in Calc III. You were introduced to the partial derivatives \partial f/\partial x and \partial f/\partial y. There is no such thing as a "\partial x".

One important reason is that the partial derivatives themselves just don't tell you enough about the function. If the derivative of a function of one variable exists at a point, then it is differentiable (and so continuous) at that point. A function of several variables can have all its partial derivatives at a point and still not be differentiable nor even continuous at that point.

Take f(x,y)= 0 if xy= 0, 1 otherwise. It is easy to show that \partial f/\partial x= \partial f/\partial y= 0 at (0,0) but f is not even continuous there.
 


Thanks, that cleared things up for me, HallsofIvy.
 

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