Difference Between Partial and Ordinary Differentials

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SUMMARY

The discussion clarifies the distinction between ordinary differentials and partial derivatives in calculus. Ordinary differentials, represented as dx, are quantities that can be manipulated algebraically, as shown in the chain rule dy/dx = (dy/du)(du/dx). In contrast, partial derivatives, denoted as ∂f/∂x and ∂f/∂y, do not represent quantities in the same way and can exist without ensuring the function's differentiability or continuity. The example provided, f(x,y) = 0 if xy = 0, 1 otherwise, illustrates that a function can have zero partial derivatives at a point while being discontinuous.

PREREQUISITES
  • Understanding of basic calculus concepts, including derivatives and the chain rule.
  • Familiarity with partial derivatives and their notation, specifically ∂f/∂x and ∂f/∂y.
  • Knowledge of continuity and differentiability in the context of functions of multiple variables.
  • Experience with examples of functions that demonstrate the properties of partial derivatives.
NEXT STEPS
  • Study the properties of partial derivatives in multivariable calculus.
  • Learn about the implications of continuity and differentiability in functions of several variables.
  • Explore advanced topics such as the differentiability of functions and the concept of limits in higher dimensions.
  • Investigate examples of functions that exhibit discontinuity despite having defined partial derivatives.
USEFUL FOR

Students and educators in mathematics, particularly those studying calculus and multivariable functions, as well as anyone seeking to deepen their understanding of the differences between ordinary and partial differentials.

Pinu7
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I have been wanting to ask this for a while.

In Calc I, I was introduced to differentials. It seemed like they act like quantities(please corrected me if I'm wrong). For example dx/dx=1. You can obtain this by differentiating x or by eliminating the dx in the numerator and denominator(I do not know why this worked).

What convinced me that differentials where quantities was the chain rule. dy/dx=(dy/du)(du/dx). The proof is a bit tough, but you will obtain the same result by eliminating the du.(I may be making a TREMENDOUS mathematical blunder here, but it seemes to work)

In Calc III, I was introduced to [tex]\partial[/tex]x and[tex]\partial[/tex]y. Obviously I found out that [tex]\partial[/tex]x[tex]\neq[/tex]dx or else the chain rule for multiple variables would not simplify to dz/du.

So, why are these two infinitesimals so different?
 
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No, you were not "introduced to [itex]\partial x[/itex] and [itex]\partial y[/itex] in Calc III. You were introduced to the partial derivatives [itex]\partial f/\partial x[/itex] and [itex]\partial f/\partial y[/itex]. There is no such thing as a "[itex]\partial x[/itex]".

One important reason is that the partial derivatives themselves just don't tell you enough about the function. If the derivative of a function of one variable exists at a point, then it is differentiable (and so continuous) at that point. A function of several variables can have all its partial derivatives at a point and still not be differentiable nor even continuous at that point.

Take f(x,y)= 0 if xy= 0, 1 otherwise. It is easy to show that [itex]\partial f/\partial x= \partial f/\partial y= 0[/itex] at (0,0) but f is not even continuous there.
 


Thanks, that cleared things up for me, HallsofIvy.
 

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