(adsbygoogle = window.adsbygoogle || []).push({}); Given that the equation

t d^2y/dt^2 - (1+3t) dy/dt + 3y = 0. has a solution of the form e^ct, for some constant c, find the general solution (The answer is y(t) = c1(1+3t) + c2e^(3t)

Edit: I finished this question as i figured it out. but when i come down to the last step, i get this

y1(t) = e^3t

y2(t) = -1/3t - 1/9

y(t) = c1y1(t) + c2y2(t)

y(t) = c1e^3t + c2(-1/3t-1/9)

y(t) = c1e^3t + -1/9c2(3t+1)

can i bet c3 = -1/9c2???

so it's

y(t) = c1e^3t + c3(3t+1)

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Differential equations - 2nd order homogenous eq'n w/ unknown

**Physics Forums | Science Articles, Homework Help, Discussion**